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goblinko [34]
2 years ago
15

Carbohydrates serve as a vital source of chemical energy to the human body. Carbohydrates are broken down into smaller units of

glucose, among other sugars, providing energy to various muscles and organs, including the brain. On average, for every 8.00 g of carbohydrates consumed, the body will store 136 kJ of energy.
Convert this energy value to kilocalories (kcal).
Chemistry
1 answer:
fredd [130]2 years ago
5 0

Answer:

711.8 Kilocalories

Explanation:

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Question 096 Propose a three-step synthetic sequence to accomplish the transformation below. 1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2C
salantis [7]

Complete Question

Question 096 Propose a three-step synthetic sequence to accomplish the transformation below.

Option 1 =>  1) HBr, ROOR; 2) t-BuOK; 3) CH3CH2CCNa

Option 2 => 1) NaOEt; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 3 => 1) t-BuOK; 2) NaNH2; 3) CH3CH2CCNa

Option 4 => 1) CH3CH2CH2CH2Br; 2) NaOEt; 3) HBr, ROOR

Option 5 => 1) t-BuOK; 2) HBr, ROOR; 3) CH3CH2CCNa

Option 6 => 1) NaOEt; 2) NBS, hν; 3) NaSBu

Answer:

The correct option is option 5

Explanation:

   The mechanism of the reaction is shown on the first uploaded image

8 0
2 years ago
Na3X, Enter the group number of X?
Katen [24]
X will be in group 5, since if you exchange the valencies of Na with any element on group 5, you will get Na3X
4 0
2 years ago
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How many ions are there in 0.187 mol of Na+ ions
kondaur [170]
Best Answer
1 mole of a substance contains 6.022x10^23 "units" of that substance.

So 0.187 mol of Na+ is 1.13x10^23 ions (6.022x10^23 x 0.187).
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How many moles of gas Does it take to occupy 520 mL at a pressure of 400 torr and a temperature of 340 k
Ann [662]
Answer would be B. I provided work on an image attached. Message me if u have any other questions on how to do it

6 0
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Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
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2 years ago
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