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zepelin [54]
1 year ago
11

A calculator is broken so that the only keys that still work are the $\sin$, $\cos$, $\tan$, $\cot$, $\arcsin$, $\arccos$, and $

\arctan$ buttons. Assume that the calculator does real number calculations with infinite precision. All functions are in terms of radians, and you may assume all the values of $x$ below are positive. (a) Find, with proof, a sequence of buttons that will transform $x$ into $\frac{1}{x}$ . (b) Find, with proof, a sequence of buttons that will transform $\sqrt x$ into $\sqrt{x 1}$. (c) The display initially shows $1$. Prove that there is a sequence of buttons that will produce $\frac{3}{\sqrt{5}}$.
Mathematics
1 answer:
miskamm [114]1 year ago
7 0
What is this check the q again
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Last Saturday they were 1486 people at the Cineplex. There were about the same number of people in each of the six theaters. Bet
padilas [110]
When you do 1486x6 it equals 8,916
4 0
1 year ago
Nswer two questions about Systems A AA and B BB: System A AA start text, end text System B BB { − 3 x + 12 y = 15 7 x − 10 y = −
rjkz [21]

Answer:

(Choice C) C Replace one equation with a multiple of itself

Step-by-step explanation:

Since system A has the equations

-3x + 12y = 15 and 7x - 10y = -2 and,

system B has the equations

-x + 4y = 5 and 7x - 10 y = -2.

To get system B from system A, we notice that equation -x + 4y = 5 is a multiple of -3x + 12y = 15 ⇒ 3(-x + 4y = 5) = (-3x + 12y = 15).

So, (-x + 4y = 5) = (1/3) × (-3x + 12y = 15)

So, we replace the first equation in system B by 1/3 the first equation in system A to obtain the first equation in system B.

So, choice C is the answer.

We replace one equation with a multiple of itself.

7 0
1 year ago
Howmet Corporation needs $200,000 in 5 years.
Bogdan [553]
:)
The formula of the future value of annuity ordinary is
Fv=pmt [(1+r/k)^(kn)-1)÷(r/n)]
So we need to solve for pmt
Pmt=fv÷[(1+r/k)^(kn)-1)÷(r/n)]
Pmt=200,000÷(((1+0.10÷4)^(4×5)
−1)÷(0.10÷4))=7,829.43...answer

Hope it helps
3 0
2 years ago
A law school administrator was interested in whether a student's score on the entrance exam can be used to predict a student's g
frutty [35]

Answer:

The correlation coeffcient for this case was provided:

r =0.934

And this coefficient is very near to 1 the maximum possible value, so then we can interpret that the relationship between the entrace exam score and the grade point average are strongly linearly correlated .

We can also find the r^2 who represent the determination coefficient and we got:

r^2 = 0.934^2= 0.872

And the interpretation for this is that a linear model explains appproximately 87.2% of the variability between the two variables

Step-by-step explanation:

Previous concepts

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:  

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

The correlation coeffcient for this case was provided:

r =0.934

And this coefficient is very near to 1 the maximum possible value, so then we can interpret that the relationship between the entrace exam score and the grade point average are strongly linearly correlated .

We can also find the r^2 who represent the determination coefficient and we got:

r^2 = 0.934^2= 0.872

And the interpretation for this is that a linear model explains appproximately 87.2% of the variability between the two variables

8 0
1 year ago
Suppose 1000 people enter a chess tournament. Use a rooted tree model of the tournament to determine how many games must be play
Vlada [557]

Answer: 999 games

Step-by-step explanation:

There are many ways to illustrate the rooted tree model to calculate the number of games that must be played until only one player is left who has not lost.

We could go about this manually. Though this would be somewhat tedious, I have done it and attached it to this answer. Note that when the number of players is odd, an extra game has to be played to ensure that all entrants at that round of the tournament have played at least one game at that round. Note that there is no limit on the number of games a player can play; the only condition is that a player is eliminated once the player loses.

The sum of the figures in the third column is 999.

We could also use the formula for rooted trees to calculate the number of games that would be played.

i=\frac{l - 1}{m - 1}

where i is the number of "internal nodes," which represents the number of games played for an "<em>m</em>-ary" tree, which is the number of players involved in each game and l is known as "the number of leaves," in this case, the number of players.

The number of players is 1000 and each game involves 2 players. Therefore, the number of games played, i, is given by

i=\frac{l - 1}{m - 1} = i=\frac{1000 - 1}{2 - 1} = \frac{999}{1} =999

7 0
1 year ago
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