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2 years ago

In which orbitals would the valence electrons for carbon c. be placed?

Chemistry

2 answers:

katrin2010 [14]2 years ago

8 0

Answer: 2s and 2p

Explanation: Carbon is an element with atomic number of 6 and thus contains 6 electrons. The electrons are filled in order of increasing energies and follows Afbau's rule.The electrons are singly filled first in each orbital having same spin, then only pairing occurs. This rule was known as Hund's Rule.

The valence electrons are the electrons which are present in last shell. Thus valence electrons are 4, two in s and 2 in p orbitals.

$C: 6:1s^22s^22p_x^12p_y^1$

telo118 [61]2 years ago

3 0

The answer is: 2s and 2p orbitals.

Carbon (C) is a chemical element with atomic number 6. It has 6 protons and 6 electrons.

Electron configuration for carbon: ₆C 1s² 2s² 2p².

Valence electrons are in 2s and 2p orbitals.

There is one pair of electrons in 2s orbital and two lone electrons in 2p orbital with the same electron spin.

Carbon is in group 14 of periodic table group.

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A student described two properties of a substance shown below which of the following is true about the two properties described

mel-nik [20]

Answer:

Explanation:

catches fire easily, there is a chemical in the substance that reacts to the flame, and a key to it being a chemical property is when exposed to other substances, there is a chemical in the other substances that makes it chemically react

7 0

2 years ago

Read 2 more answers

Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −

kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3) ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca) = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207 KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH of the respective molecules given above,

ΔH = -1270 + (-393.5) - (-1207)

ΔH = -456.5 KJ

8 0

2 years ago

After going through a guided tutorial by selecting Run Grams Demonstration, you can create your own experiment by clicking the R

Step2247 [10]

Answer: Thus 24.0 g of $SO_2$ would be needed.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{6.00g}{32g/mol}=0.1875moles$

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(l)$

According to stoichiometry :

1 mole of $O_2$ require = 2 moles of $SO_2$

Thus 0.1875 moles of $O_2$ will require= $\frac{2}{1}\times 0.1875=0.375moles$ of $SO_2$

Mass of $SO_2=moles\times {\text {Molar mass}}=0.375moles\times 64g/mol=24.0g$

Thus 24.0 g of $SO_2$ would be needed to completely react with 6.00 g of $O_2$ such that all reactants could be consumed.

5 0

2 years ago

A load of bauxite has a density of 3.11 . If the mass of the load is 220. metric tons, how many dump trucks, each with a capacit

kicyunya [14]

Answer : The number of dump trucks required are, 8

Explanation : Given,

Density of load of bauxite = $3.11g/cm^3$

Mass of load = 220 metric tons = $220\times 10^6g$

conversions used : 1 metric ton = 1000000 g

First w have to calculate the volume of load of bauxite.

$Volume=\frac{Mass}{Density}$

$Volume=\frac{220\times 10^6g}{3.11g/cm^3}=7.07\times 10^7cm^3$

Convert cubic centimeter to cubic yard:

$1cm^3=1.30795\times 10^{-6}yards^3$

So,

Volume of load = $\frac{1.30795\times 10^{-6}yards^3}{1cm^3}\times (7.07\times 10^7cm^3)$

Volume of load = 92.47 cubic yards

Now we have to calculate the number of dump trucks.

Capacity of a dump truck = 11 cubic yard

Number of trump trucks required = $\frac{92.47\text{ cubic yard}}{11\text {cubic yard}}=8.406\approx 8$

Thus, the number of dump trucks required are, 8

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2 years ago

Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

mote1985 [20]

Answer:

Unfavorable reactions: Reaction A and Reaction B.

Coupled reactions favorable: Reactions B and C and Reactions A and C.

Net change:

Reactions B and C : -14.2kJ/mol

Reactions A and B : 30.1kJ/mol

Reactions A and C: -16.7kJ/mol

Explanation:

A reaction is thermodynamically favorable (spontaneous) if ΔG < 0. Thus, the unfavorable reactions -ΔG > 0- are:

Reaction A and reaction B.

When reaction C is coupled with reaction B and reaction A the chemical equation is:

ATP + fructose-1,6-phosphate ⟶ ADP + fructose-1,6-bisphosphate

ΔG = 16.3 - 30.5 = -14.2 kJ/mol

ATP + glucose ⟶ ADP + glucose-6-phosphate

ΔG = 13.8 - 30.5 = -16.7 kJ/mol

The coupled reaction of A and B has a change in free energy of:

ΔG = 13.8 + 16.3 = 30.1 kJ/mol

4 0

2 years ago