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vlabodo [156]
2 years ago
5

A hotel has 270 units. All rooms are occupied when the hotel changes $90 per day for a room. For every increase of x dollars in

the daily room rate, there are x rooms vacant. Each occupied room costs $28 per day to service and maintain. What should the hotel charge per day in order to maximize daily profit?
Mathematics
1 answer:
Brut [27]2 years ago
4 0
62 dollars i think tho i'm not very sure, sorry for not knowing exactly but god bless and have a good day/night/week/month/year/life <3
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To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne
Naily [24]

Answer:

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

\hat p=\frac{67}{150}=0.447 estimated proportion of applicants who request financial aid

p_o=0.35 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

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A Sunday newspaper lists the 10 used car prices for a foreign compact, with age x measured in years and selling price y measured
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Question:

A Sunday newspaper lists the 10 used car prices for a foreign compact, with age x measured in years and selling price y measured in thousands of dollars. A Sunday newspaper lists the 10 used car prices for a foreign compact, with age x measured in years and selling price y measured in thousands of dollars.

Picture of data can be found in the picture attached.

Answer:

Slope = -1.71

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Step-by-step explanation:

Equation of a line usually takes the general form :

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Inputting the data into a linear regression calculator ;

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Comparing the output to the general formula;

The slope (m):

m = -1.70872 = -1.71(2 decimal places).

The intercept (c):

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