Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
Answer:
15
Step-by-step explanation:
Given that a1 = 6
an = 3 + 2(an-1),
Substitute n = 2 into the formula
a2 = 3 + 2(a1)
a2 = 3 + 2(6)
a2 = 3+12
a2 = 15
Hence the second term of the sequence is 15
Answer:
$2.25/km
Step-by-step explanation:
The cost charged for a total taxi ride of
was $32. To get the cost per km, we divide the cost charged for the total taxi ride by the total distance that was traveled by the taxi. The cost per km is given by:
Cost per km = 
Therefore the cost per kilometer is $2.25 per kilometer. Each kilometer traveled by the taxi cost $2.25.
Answer:
24 cm
Step-by-step explanation:
Given: Picture of the star is made up of 4 unshaded equilateral triangles of equal area and a shaded square.
Area of the shaded region (square) = 
To find: the perimeter of the star
Solution:
Area of the shaded region (square) = 
Area of square = 

As each equilateral triangle has side lengths that are the same as the side length of the square,
length of side of the star = 3 cm
Perimeter is the sum of lengths of the sides.
Perimeter of star = sum of 8 sides of the star
= 8 × 3 = 24 cm
A. 2x3=6 and 6x12=72 so 78 is greater than 36
6+72=79 which is less than 90