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2 years ago

8

jeanette wants to tile the floor of a room in her house. the square tiles measure 3/4 ft on each side. the room is 10 ft wide. w

rite and solve an inequality to describe how many tiles are needed to make 1 row

2 answers:

Yuri [45]2 years ago

4 0

First off i dont like using fractions so i will convert 3/4 into 0.75 to start. Then i would divide 0.75 into 10 and that equals 13 and 1/3

The answer is 13 tiles and 1/3 of a tile to make one row

Crazy boy [7]2 years ago

4 0

Answer:

14

Step-by-step explanation:

Late the number of tile =x .

According to question we can write .

$\frac{3}{4} *x\geq 10$

$x\geq 10*\frac{4}{3}$

$x\geq \frac{40}{3}\\x\geq 13\frac{1}{3} \\$

Since the number of tiles cannot be in fraction or decimal hence the number of required tiles is 14

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A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t

denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

$\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5$

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

$\widehat{Y}=Y_1+Y_2+...+Y_{200}$

= $200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs$

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

S= $\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486$

Then, the standard error of $\widehat{Y} is$

$\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:$ =83.785

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]$

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

$\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45$

The sample ratio is

$r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}$ =0.1 , this is also the estimate of the population ratio R= $\frac{\overline{Y}}{\overline{X}} .$

Therefore, the estimated total weight of grain in the population using ratio estimator is

$\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\,$ lbs

4) The variance of the ratio estimator is

var(r)= $\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1} , where \mu_x=8800/200=44lbs$

= $\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005$

Hence, the standard error of the estimate of the total population is

$\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:$ =21.556

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]$

8 0

2 years ago

Read 2 more answers

The cafeteria staff made sandwiches. Each sandwich had either rye or white bread, either ham or turkey, and either cheese or no

Anit [1.1K]

Answer:

1/2 (1 half)

Step-by-step explanation:

The number of different sandwiches is calculated multiplying all of the possibilities for each material used:

rye or white bread: 2 options

ham or turkey: 2 options

cheese or no cheese: 2 options

So the number of different sandwiches that can be made is 2*2*2 = 8.

From these 8 different sandwiches, 4 have cheese and 4 have no cheese, as the staff made a equal number of each type of sandwich.

So, if from 8 different type of sandwiches, 4 have cheese, the chances of Mary getting a sandwich with cheese is 4/8 = 1/2 (1 half).

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2 years ago

Leona purchased a $1,000 bond having a quoted price of 99.875. She had to pay a 5.5% brokerage fee (of the selling price). What

Zina [86]

Answer:

The total cost of the bond is none of the given choices.

Step-by-step explanation:

The selling price of a $1000 bond = $99.875

The brokerage fee = 5.5 %

Now, 5.5% of $99.875 = $\frac{5.5}{100} \times 99.875 = 5.493$

So, the brokerage fee = $5.493

Now, to find out the total cost of the bond:

Total Cost = The selling Price + Brokerage Price

= $99.875 + $5.493

= $105.368

or, the total price of the $1000 bond is $ 105.368.

Hence, the total cost of the bond is none of the given choices.

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2 years ago

the chorus has 35 members. which expression represents the number of ways a group of 6 members can be chosen to do a special per

zimovet [89]

You have to choose $6$ members from the group of $35$ people. So there are $\binom{35}{6}$ ways to do it.

3 0

1 year ago

Read 2 more answers

jake makes 9 loaves of olive bread. he uses 30 grams of olives in each loaf.he started with 1 kilogram of olives.how many grams

8090 [49]

Considering that 1 kilogram is equal to 1000 grams and he made 9 loaves of bread using 30 grams each time, that equates to 270 grams of olives. 1000 - 270 = 730. Your answer is 730 grams of olives remain. Hope this helped.

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2 years ago