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2 years ago

10

Two numbers have the same digit in the millions period, the same digits in the thousands period, and the same digits in the ones

period. Do these two numbers have the same value? Explain.

1 answer:

kompoz [17]2 years ago

5 0

No. the tenths may not be the same

:))

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Each gallon of paint covers $200$ square feet. I have to paint one side of a wall that is $12$ meters tall and $80$ meters long.

dsp73

Answer:

make those cheeks go in circuler motion

Step-by-step explanation:

5 0

2 years ago

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Use the binomial theorem to ﬁnd the coeﬃcient of xayb in the expansion of (5x2 + 2y3)6, where a) a = 6, b = 9. b) a = 2, b = 15.

goldfiish [28.3K]

Answer:

Step-by-step explanation:

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

1 6 15 20 15 6 1

1 6 15 20 15 6 1

we use these for the expansion of (5x² + 2y³)⁶

1(5x²)⁶(2y³)⁰ + 6(5x²)⁵(2y³)¹ + 15(5x²)⁴(2y³)² + 20(5x²)³(2y³)³+ 15(5x²)²(2y³)⁴+ 6(5x²)¹(2y³)⁵ + 1(5x²)⁰(2y³)⁶

78125ₓ¹²+187500ₓ¹⁰ y³ +37500ₓ⁸y⁶+20000ₓ⁶y⁹+6000x⁴y¹²+960x²y¹⁵+2y¹⁸

a.)a = 6, b = 9. the coeﬃcient of xᵃyᵇ ( 20000ₓ⁶y⁹) = 20000

b) a = 2, b = 15. the coeﬃcient of xᵃyᵇ ( 960x²y¹⁵) = 960

c) a = 3, b = 12. the coeﬃcient of xᵃyᵇ is not present

d) a = 12, b = 0 the coeﬃcient of xᵃyᵇ ( 78125ₓ¹²) = 78125

e) a = 8, b = 9. the coeﬃcient of xᵃyᵇ is not present

7 0

2 years ago

On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne

nasty-shy [4]

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ then,

$x=\frac{x_{1}+x_{2}}{2}$

$y=\frac{y_{1}+y_{2}}{2}$

In a parallelogram, its diagonals intersect each other at their mid-points

that means its diagonals bisect each other

∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

∵ H = (-2 , 2)

∵ J = (4 , -2)

- Find the mid point of HJ

∵ $M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})$

∴ $M_{HJ}=(\frac{2}{2},\frac{0}{2})$

∴ $M_{HJ}=(1,0)$

∴ The mid-point of HJ is (1 , 0)

∵ I = (4 , 3)

∵ K = (-2 , -3)

- Find the mid point of IK

∵ $M_{IK}=(\frac{4+-2}{2},\frac{3+-3}{2})$

∴ $M_{IK}=(\frac{2}{2},\frac{0}{2})$

∴ $M_{IK}=(1,0)$

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

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1 year ago

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Seven Applicants for a Job - F, G, H, I, J, K, and L are each to be interviewed on monday or Tuesday . Each

stiks02 [169]

Answer:

I would guess its D. Because it is the one that makes the most sense.

Step-by-step explanation:

H and L has to be on the same day with no other application so not A, B, or C because there is L in all of them.

Hope I helped!

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1 year ago

y - 5 = 0.5x2 + 6x - 3 How many x-intercepts does the graph of this quadratic have? Two x-intercepts One x-intercept No x-interc

inysia [295]

Here, if you have any questions feel free to ask

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2 years ago

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