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2 years ago

What is a multiple of 72

Mathematics

2 answers:

xxMikexx [17]2 years ago

7 0

There are an infinite number of them.

A few are:

72
144
216
2160
72 trillion
.
.
etc.

Alona [7]2 years ago

5 0

There are many answes for this problem. some are 72.,144,216,288 360,etc...

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The vertices of ΔRST are R(–1,–1), S(–1,11) and T(4,11). Which could be the side lengths of a triangle that is similar but not c

Step2247 [10]

The side lengths could be 10, 24 and 26 units.

We must first find the side lengths. We use the distance formula to do this.

For RT:
$d=\sqrt{(11--1)^2+(-1--1)^2}
\\=\sqrt{(11+1)^2+(-1+1)^2}
\\=\sqrt{12^2+0^2}=\sqrt{144}=12$

For ST:
$d=\sqrt{(11-11)^2+(4--1)^2}
\\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5$

For TR:
$d=\sqrt{(11--1)^2+(4--1)^2}
\\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13$

Our side lengths, from least to greatest, are 5, 12 and 13.

To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length. 10, 24 and 26 are all 2x the original side lengths, so this works.

5 0

2 years ago

There were 200 members at a skating club. After some new members went in, there were 256 members altogether at the skating club.

mojhsa [17]

If I think I’m understanding it, the new members out of the 200 original would be adding 28% to the mix

4 0

2 years ago

I NEED HELP PLEASE! Jenny's birthday cake is circular and has a 30 cm radius. Her slice creates an arc of with a central angle o

dybincka [34]

Ok, so if the angle is 120 degrees, its one third of the full cake (which is 360 degrees). So the area of the whole circle (worked out with area = pi * r^2 where r is 30) gives 900*pi, and so one third of that (because her slice is one third) is 300pi.

3 0

2 years ago

If mJI = (3x+2)°, mHLK = (15x-36)°, and m∠HML = (8x-1)°, find mHLK

Gala2k [10]

Answer:

The value of mHLK will be "(204)°".

Step-by-step explanation:

The given values are:

mJI = (3x+2)°

mHLK = (15x-36)°

and,

m∠HML = (8x-1)°

then,

mHLK = ?

Now,

By using chord-chord formula of angle, we get

$mHMK=\frac{1}{2}(mJL+mHLK)$

On putting the values in the above formula, we get

⇒ $(8x-1)=\frac{1}{2}(15x-36+3x+2)$

On applying cross-multiplication, we get

⇒ $2(8x-1)=18x-34$

⇒ $16x-2=18x-34$

On subtracting "18x" from both sides, we get

⇒ $16x-2-18x=18x-34-18x$

⇒ $-2x-2=-34$

On adding "2" both sides, we get

⇒ $-2x=-34+2$

⇒ $-2x=-32$

⇒ $x=\frac{32}{2}$

⇒ $x=16$

On putting the value of "x" in mHLK = (15x-36)°, we get

⇒ (15x-36)° = (15×16-36)°

⇒ = (240-36)°

⇒ = (204)°

So that mHLK = (204)°

4 0

2 years ago

the line y=2x-4 and the parabola y=x^2- 4 intersect in the standard x,y coordinate plane if point a s,t is at an intersection of

mylen [45]

2x-4=x^2-4
-4=x^2-2x-4 (start moving everything to one side)
x^2-2x=0 (the 4 cancel out)
x(x-2)=0 (factor out an x)
x=0 & x=2 (solved for x)

y=2x-4 (pick one of the equations)
y=2(0)-4 (plug in x)
y=-4
(0,-4)

y=2(2)-4 (plug in the second point)
y=0
(2,0)

The greatest possible value of s is 2. (2,0)

7 0

2 years ago