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tresset_1 [31]
2 years ago
15

Two factors of –48 have a difference of 19. The factor with a greater absolute value is positive.

Mathematics
2 answers:
Alexeev081 [22]2 years ago
8 0

Answer:  Option C, 13

Explanation:

Two possible factors of -48 are -16 ,3 or  -3, 16

And difference is greater number minus smaller number we will get as below

3-(-16) = 19 or 16-(-3) = 19

Case 1: two factors are -16 and 3

sum of factors = -16 +3 = -13

Now, we take absolute value of sum of factors |-13| = 13

Case 2: two factors are 16 and -3

sum of factors = 16 -3 = 13

Now, we take absolute value of sum of factors |13| = 13

so, C is the correct option




Luden [163]2 years ago
7 0

===>Factors of −48 with smaller absolute value negative:
smaller factor          larger factor           difference
-1                                 48                           49
-2                                 24                           26
-3                                 16                           19

Add: -3 + 16 = 13
Therefore, the answer to this item is letter c.13.

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2 years ago
The sum of two polynomials is 8d5 – 3c3d2 + 5c2d3 – 4cd4 + 9. If one addend is 2d5 – c3d2 + 8cd4 + 1, what is the other addend?
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Answer: The correct option is A.

Step-by-step explanation: We are given a polynomial which is a sum of other 2 polynomials.

We are given the resultant polynomial which is : 8d^5-3c^3d^2+5c^2d^3-4cd^4+9

One of the polynomial which are added up is : 2d^5-c^3d^2+8cd^4+1

Let the other polynomial be 'x'

According to the question:

8d^5-3c^3d^2+5c^2d^3-4cd^4+9=x+(2d^5-c^3d^2+8cd^4+1)

x=8d^5-3c^3d^2+5c^2d^3-4cd^4+9-(2d^5-c^3d^2+8cd^4+1)

Solving the like terms in above equation we get:

x=(8d^5-2d^5)+(-3c^3d^2+c^3d^2)+(5c^2d^3)+(-4cd^4-8cd^4)+(9-1)

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Answer:

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Assuming that a fair die is rolled.

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Let  X  be the set of all possible outcomes. Let  A  be an outcome.

So, the probability that  A  occurs is:

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As the set of all possible outcomes of the roll of a single die is:

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                   P\left(8\right)=0

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