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Tatiana [17]
2 years ago
4

Enrique has $50 in his lunch account and spends $5 per day from the account. Maya has $46 in her lunch account and spends $4 per

day from the account. Which equations model the situation?
50 – 5x = y and 46 – 4x = y
5x + 50 = y and 4x + 46 = y
5x – 50 = y and 4x – 46 = y
5 – 50x = y and 4 – 46x = y
Mathematics
2 answers:
iragen [17]2 years ago
9 0

Answer:

<h3>A) 50 – 5x = y and 46 – 4x = y </h3>

stiv31 [10]2 years ago
5 0
Enrique has 50$ in his lunch account and spends 5<span>$ per day from the account. 
</span>This means, that in order to get how much money Enrique has in his account (y) left we should subtract the money he spends from the total amount:
50-5*x=y, where x is the number of days, and the product 5*x gives the amount of money Enrique spends for X days. 
Similar to this , Maya has 50$ in his lunch account and spends 4<span>$ per day. So, she has left:
</span><span>26-4*x=y.
</span>
So, the first equation models the described situation. 
<span>50 – 5x = y and 46 – 4x = y</span>
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Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

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And if we replace we got: \bar X=10.65

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8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

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Median =\frac{10.7+10.7}{2}=10.7

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Mode= 10.7

Part b

The range is defined as Range =Max-Min and if we replace we got:

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s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

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Part c

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IQR = Q_3 -Q_1 = 11.05-10.55=0.5

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