Answer:
The answer is "Unstructured"
Explanation:
In comparison, unstructured information applies to information, which doesn't suit the conventional column and rows concerning databases properly. It is also known as sources, that include mails, audio and video files, web pages and posts in communication networks.
- This tracks and communicates on travel and object flow-through sensors and much more.
- These types of data are used in both companies and organizations.
Answer:
<u>The total time elapsed from the time a bit is created (from the original analog signal at Host A) until the bit is decoded (as part of the analog signal at Host B is </u><u>25.11 ms</u>
Explanation:
Host A first converts the analog signal to a digital 64kbps stream and then groups it into 56-byte packets. The time taken for this can be calculated as:
time taken 1= 
= (56 x 8) bits / 64 x 10³ bits/s
= 7 x 10⁻³s
time taken 1= 7 ms
The transmission rate of the packet from Host A to Host B is 4 Mbps. The time taken to transfer the packets can be calculated as:
time taken 2= (56 x 8) bits / 4 x 10⁶ bits/s
= 1.12 x 10⁻⁴ s
time taken 2= 112 μs
The propagation delay is 18 ms.
To calculate the total time elapsed, we need to add up all the time taken at each individual stage.
<u />
<u> = Time taken 1 + Time taken 2 + Propagation Delay</u>
= 7 ms + 112 μs + 18 ms
= 0.025112 s
= 25.11 ms
Answer:
int withinArray(int * intArray, int size, int * ptr) {
if(ptr == NULL) // if ptr == NULL return 0
return 0;
// if end of intArr is reached
if(size == 0)
return 0; // element not found
else
{
if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr
return 1; // return 1
return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements
}
}
Explanation:
Above is the completion of the program.