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2 years ago

Which organization supports professionals who assist families in making informed choices about products and services?

2 answers:

6 0

The organisation that would best aid families and choose the right products to buy would be the American Association of Family and Consumer Sciences. In addition, the institution is primarily composed of home economists wherein these professionals promote efficient consumer consumption of goods.

GenaCL600 [577]2 years ago

5 0

The right option is; C) American Association of Family and Consumer Sciences

American Association of Family and Consumer Sciences is the organization that supports professionals who assist families in making informed choices about products and services.

American Association of Family and Consumer Sciences is a nonprofit professional association in America that supports professionals in the aspect of family and consumer sciences. The association leads and supports professionals who assist families, individuals and communities in making informed choices about their health, relationships, and products and services. The association was created by Ellen H. Richards in 1908 and it has 5,000 professionals as its member.

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________ is free software created and updated by a worldwide community of programmers. office software a web service cloud-based

Yanka [14]

I would thing ios or apple cloud personally.

6 0

1 year ago

Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*

natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3() d, e, f

fun2() c, d, e

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "c" of fun2() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3() d, e, f

fun1() b, c, d

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun3().

In fun3(), the local variables "d, e, f" of fun3() will be visible

variable "b, c" of fun1() will be visible

variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1() b, c, d

fun3() d, e, f

fun2() c, d, e

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun1().

In fun1(), the local variables "b, c, d" of fun1() will be visible

variable "e, f" of fun3() will be visible

variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2() c, d, e

fun3() d, e, f

fun1() b, c, d,

main() a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

From the above call stack diagram, it is very clear that the last function call is made to fun2().

In fun2(), the local variables "c, d, e" of fun2() will be visible

variable "f" of fun3() will be visible

variable "b" of fun1() will be visible

variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

8 0

1 year ago

The most commonly used method to connect to a WAN is through the telephone system. To do so, what piece of equipment would you r

Step2247 [10]

Modems create an analog signal that carries digital data on it,
and strip the digital data from an analog signal that they receive.
That's what's needed to connect through the telephone system,
since the telephone system is still one big analog system.

8 0

2 years ago

Read 2 more answers

What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C

Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100 -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70 -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice) -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref) -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80 -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20 -> This line adds 20 to the value of Cost and assigns the result to Cost variable

End Subprogram -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e. Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80

7 0

1 year ago

2.4: Star Pattern Write a program that displays the following pattern: * *** ***** ******* ***** *** * Output. Seven lines of ou

adelina 88 [10]

Answer:

// here is code in java.

public class NAMES

{

// main method

public static void main(String[] args)

{

int n=4;

// print the upper half

for(int a=1;a<=n;a++)

{

for(int b=1;b<=n-a;b++)

{

// print the spaces

System.out.print(" ");

}

// print the * of upper half

for(int x=1;x<=a*2-1;x++)

{

// print the *

System.out.print("*");

}

// print newline

System.out.println();

}

// print the lower half

for(int y=n-1;y>0;y--)

{

for(int z=1;z<=n-y;z++)

{

// print the spaces

System.out.print(" ");

}

for(int m=1;m<=y*2-1;m++)

{

// print the *

System.out.print("*");

}

// print newline

System.out.println();

}

Explanation:

Declare a variable "n" and initialize it with 4. First print the spaces (" ") of the upper half with the help of nested for loop.Then print the "*" of the upper half with for loop. Similarly print the lower half in revers order. This will print the required shape.

Output:

***

*****

*******

*****

***

5 0

2 years ago