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igor_vitrenko [27]
2 years ago
10

A team of swimmers is training for a swim meet. The table shows the number of laps each person has swum so far and how long the

laps took. Name Laps Time (minutes) Jonathan 2 4 Julian 1 1 Seth 3 6 Bennett 7 21 Taylor 4 7 The relationship between time and the number of laps is not proportional across all swimmers. Which two swimmers swam at the same rate (had time and laps in the same proportion)?
Mathematics
2 answers:
Tasya [4]2 years ago
6 0
Jonathan and Seth both took 2 minutes to swim each of their laps.
densk [106]2 years ago
3 0

<u><em>Answer:</em></u>

Jonathan and Seth have the same rate

<u><em>Explanation:</em></u>

We will start by getting the rate which is the ratio \frac{laps}{minutes} for each person and then we will compare them.

<u>1- Jonathan:</u>

Completed 2 laps in 4 minutes. <u>This means that:</u>

\frac{laps}{minutes} = \frac{2}{4} = \frac{1}{2} lap/minute

<u>2- Julian:</u>

Completed 1 lap in 1 minute. <u>This means that:</u>

\frac{laps}{minutes} = \frac{1}{1} = 1 lap/minute

<u>3- Seth:</u>

Completed 3 laps in 6 minutes. <u>This means that:</u>

\frac{laps}{minutes} = \frac{3}{6} = \frac{1}{2} lap/minute

<u>4- Bennett:</u>

Completed 7 laps in 21 minutes. <u>This means that:</u>

\frac{laps}{minutes} = \frac{7}{21} = \frac{1}{3} lap/minute

<u>5- Taylor:</u>

Completed 4 laps in 7 minutes. <u>This means that:</u>

\frac{laps}{minutes} = \frac{4}{7} lap/minute

Now, comparing the above ratios (proportions), <u>we can conclude that:</u>

Both Jonathan and Seth have the same rate.

Hope this helps :)

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