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never [62]
2 years ago
4

A total interruption of processing throughout a distributed information technology system can be minimized through the use of:

Computers and Technology
1 answer:
Gnoma [55]2 years ago
5 0
The appropriate response is Fail-soft protection. Used to depict frameworks that are intended to end any unnecessary handling when there are equipment or programming disappointments. Frameworks in flop delicate mode are as yet ready to give the halfway operational ability.
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Suppose a host has a 1-MB file that is to be sent to another host. The file takes 1 second of CPU time to compress 50%, or 2 sec
kozerog [31]

Answer: bandwidth = 0.10 MB/s

Explanation:

Given

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.50 MB / Bandwidth)

Transfer Size = 0.50 MB

Total Time = Compression Time + RTT + (0.50 MB /Bandwidth)

Total Time = 1 s + RTT + (0.50 MB / Bandwidth)

Compression Time = 1 sec

Situation B:

Total Time = Compression Time + Transmission Time

Transmission Time = RTT + (1 / Bandwidth) xTransferSize

Transmission Time = RTT + (0.40 MB / Bandwidth)

Transfer Size = 0.40 MB

Total Time = Compression Time + RTT + (0.40 MB /Bandwidth)

Total Time = 2 s + RTT + (0.40 MB / Bandwidth)

Compression Time = 2 sec

Setting the total times equal:

1 s + RTT + (0.50 MB / Bandwidth) = 2 s + RTT + (0.40 MB /Bandwidth)

As the equation is simplified, the RTT term drops out(which will be discussed later):

1 s + (0.50 MB / Bandwidth) = 2 s + (0.40 MB /Bandwidth)

Like terms are collected:

(0.50 MB / Bandwidth) - (0.40 MB / Bandwidth) = 2 s - 1s

0.10 MB / Bandwidth = 1 s

Algebra is applied:

0.10 MB / 1 s = Bandwidth

Simplify:

0.10 MB/s = Bandwidth

The bandwidth, at which the two total times are equivalent, is 0.10 MB/s, or 800 kbps.

(2) . Assume the RTT for the network connection is 200 ms.

For situtation 1:  

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 1 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.50 MB

Total Time = 1.2 sec + 5 sec

Total Time = 6.2 sec

For situation 2:

Total Time = Compression Time + RTT + (1/Bandwidth) xTransferSize

Total Time = 2 sec + 0.200 sec + (1 / 0.10 MB/s) x 0.40 MB

Total Time = 2.2 sec + 4 sec

Total Time = 6.2 sec

Thus, latency is not a factor.

5 0
2 years ago
The vast amount of data collected from Internet searches, social media posts, customer transactions, military
Brums [2.3K]

Answer:

A. Big Data

Explanation:

It is big data. The internet searches, customer transactions, social media posts, medical tests, weather sensors, military surveillance, and all the data source you are seeing around yourself forms together with the big data. And a big social media company gathers around so many petabytes of data each day. And there are so many such companies, plus all sorts like eLearning sites, etc. And all these together form the big data.

3 0
2 years ago
Assume a program requires the execution of 50 x 106 FP instructions, 110 x 106 INT instructions, 80 x 106 L/S instructions, and
Molodets [167]

Explanation:

FP - 50 \times 10^6

CPI - 1

INT -110 \times 10^6,

CPI - 1

I/S - 80 \times 10^6 ,

CPI - 4

Branch - 16 \times 10^6

CPI - 2

Clock Speed - 2 \times 10^9

Time(old) =\frac{50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)}{2 x 10^9}

Time(old) = 256 \times 10^ {-3}

Time(new) =  \frac{256 \times 10^{-3}}{2}

                = 128 \times 10^{-3}

                =\frac{CPI(new) x [50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)]}{2 x 10^9}

                =  128 \times 10^{-3}

CPI(new) = \frac{-206}{50}

               = -4.12

3 0
2 years ago
Which of the following represents the bus topology? Multiple Choice All devices are connected to a central device, called a hub.
Yanka [14]

Answer: All devices are connected to a central cable or backbone.

Explanation:

"All devices are connected to a central cable or backbone". Bus Topology refers to a logical or physical network's design. Bus Topology is also the network setup for a LAN (Local Area Network) nodes connected to a "backbone" or cable. The Bus setup connects every single computer and network to a single cable. Among others, the type of cable implemented for bus topology is usually a coaxial cable.

3 0
2 years ago
How can you check an orthographic drawing to be sure there are no missing lines
user100 [1]
With an magnify glass
4 0
2 years ago
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