I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:

Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
The table showing the conversion of angle measure in degrees to angles in gradients is attached below.
In order to find the slope we divide the difference of two y-coordinates (or dependent variable which in this case is gradient measure) by the difference of two respective x-coordinates (or independent variable which in this case is degree measure).
For finding the slope we will use the first and the last point given in the table. So, the slope m will be given by:
So rounding of to nearest hundredth, the slope of line representing the conversion of degrees to gradients is 1.11
We have to identify the function which has the same set of potential rational roots as the function
.
Firstly, we will find the rational roots of the given function.
Let 'p' be the factors of 12
So, p= 
Let 'q' be the factors of 3
So, q=
So, the rational roots are given by
which are as:
.
Consider the first function given in part A.
f(x) =
Here also, Let 'p' be the factors of 12
So, p= 
Let 'q' be the factors of 3
So, q=
So, the rational roots are given by
which are as:
.
Therefore, this equation has same rational roots of the given function.
Option A is the correct answer.
Answer:
Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.
Question 14: The club was making a loss between 11.28 and 4.88 years.
Step-by-step explanation:
Question 13:
The age group y for which the response rate R is 8 microseconds is given by the solution of the equation

We graph this equation and find the solutions to be

Since only positive solutions for y are valid in the real world we take only those.
Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.
Question 14:
The footbal club is making a loss when 
Or

We graph this inequality and find the solutions to be
and 
Since in the real world only positive values for t are valid, we take the the second solution to be true.
Thus the club was making a loss in years 