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Orlov [11]
2 years ago
12

If g = 41 cm and e = 9 cm, what is the length of f?

Mathematics
2 answers:
Inga [223]2 years ago
8 0
The length of F is 32
gizmo_the_mogwai [7]2 years ago
7 0
The length of F I think is 32

I hope that helps! sorry if it wrong though.
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Joe drove 100 miles from San Francisco to Gilroy and used 4 gallons of gas. How much gas should he expect to use for a 3000-mile
erma4kov [3.2K]
750 bc u dived 3000 by 4 bc 4 is per ever 100
3 0
2 years ago
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A car company sells a scale model to of the size of one of its cars.
mixer [17]

Answer:

w = 13500 --- real windscreen

v = 408 --- scale volume

Step-by-step explanation:

Given

k = \frac{1}{10} --- scale factor

See attachment

Required

Complete the table

To get the windscreen (w) of the real car, we do the following computation

w = \frac{w_{scale}}{k^2}

This gives:

w = \frac{135}{(1/10)^2}

w = \frac{135}{1/100}

w = 13500

Next, the volume (v) of the scale mode

We make use of the following computation

v = v_{real} * k^3

So, we have:

v = 408000 * (1/10)^3

v = 408000 * 1/1000

v = 408

7 0
2 years ago
Jonah is thinking of a 2-digit number. It is a multiple of 6 and 12. It is a factor of 108. The sum of its digits is 9. What num
Colt1911 [192]

Answer:

Step-by-step explanation:

36

36x3=108

3+6=9

6 0
2 years ago
Read 2 more answers
The perimeter of the school crossing sign is 102 inches what is the length of each side
Afina-wow [57]
The perimeter of the school crossing sign is 102 inches
length of each side = ?
in the question number of sides is not mentioned, so the answer may vary for the length of each side. if there is 5 sides divide 102 by 5, we get 20.4 answer so in case of 5 sides length of each side is 20.4 inches. if there is 4 sides divide 102 by 4 and we get 25.5 inches answer for the legnth each side.
6 0
2 years ago
A rectangular storage container with an open top is to have a volume of 10m3. Thelength of its base is twice the width. Material
frutty [35]

Answer:

$163.54

Step-by-step explanation:

Volume of rectangular container = 10m^3

Length = 2(width)

Material for the base cost $10 per square meter

Material for the side cost $6 per square meter

Volume = L*B*H

L= 2W

V = (2W).W. H

10 = 2W^2.H

H = 10 /2W^2

H = 5/W^2

Let C(w) = cost function

C(w) = 10(L.W) + 6(2.L.H + 2.W.H)

= 10(2W.W) + 6(2.2W.H + 2.W.H)

= 10(2W^2) + 6(4W.H + 2.W.H)

= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)

= 20W^2 + 6(20/W + 10/W)

= 20W^2 + 6((10+20)/W)

= 20W^2 + 6(30/W)

C(w) = 20W^2 + 180/W

To find the minimum value, differentiate C with respect to w

C'(w) = 40W - 180/W^2

Put C'(w) = 0

0 = 40W - 180/W^2

40W = 180/W^2

40W^3 = 180

W^3 = 180/40

W^3 = 4.5

W = cube rt(4.5)

W = 1.65m

C = 20(1.65)^2 + 180/1.65

C = 54.45 + 109.09

C= $163.54

Minimum cost = $163.54

6 0
2 years ago
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