Given: MNFD is a trapezoid. MF ⊥ ND , NK ⊥ MD , NK = h, MN = FD. Find: Area of MNFD

After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an

galben [10]

Answer:

$y=32000(1+0.08)^x$

Step-by-step explanation:

Exponential growth function is $y=a(1+r)^x$

Where 'a' is the initial population

r is the rate of growth and x is the time period in years

a steady population of 32,000. So initial population is 32,000

an increase of 8% per year. the rate of increase is 8% that is 0.08

a= 32000 and r= 0.08

Plug in all the values in the general equation

$y=a(1+r)^x$

$y=32000(1+0.08)^x$

$y=32000(1+0.08)^x$

4 0

2 years ago

Read 2 more answers

If X is a normal random variable with parameters µ = 10 and σ 2 = 36, compute

alex41 [277]

Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

X is N(10, 6)

Or z = $\frac{x-10}{6}$

is N(0,1)

a) P(X > 5),

= $P(Z>-0.8333)\\=0.7977$

(b) P(4 < X < 16),

= $P(|z|$

(c) P(X < 8),

= $P(Z$

(d) P(X < 20),

= $P(Z$

(e) P(X > 16).

=P(Z>-0.6667)

= 0.2524

6 0

2 years ago

"High tides at a beach occur at intervals of 12 h 25 min. Yesterday, high tide was measured at 5 ft above sea level and low tide

lions [1.4K]

Answer:

13

Step-by-step explanation:

5 0

2 years ago

Bilal's fishing line was on a spool with a radius of 4 \text{ cm}4 cm4, start text, space, c, m, end text. Suddenly, a fish pull

Fantom [35]

Answer:

The distance the fish pulled the fishing line is <u>401.92 cm.</u>

Step-by-step explanation:

Given:

Radius of fishing spool = 4 cm.

Fish pulled on the line, and the spool spun 16 times before Bilal began to reel in the fish.

Now, to find the distance the fish pulled the fishing line.

So, to get the circumference of the spool first we put formula:

Radius(r) = 4 cm.

Value of π = 3.14.

$Circumference = 2\pi r$

$Circumference=2\times 3.14\times 4$

$Circumference=25.12\ cm.$

<em>As given, fish pulled on the line, and the spool spun 16 times before Bilal began to reel in the fish.</em>

Now, to get the distance the fish pulled the fishing line, we multiply 16 with the circumference:

$16\times 25.12\\\\=401.92\ cm.$

Therefore, the distance the fish pulled the fishing line is 401.92 cm.

3 0

2 years ago

A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat

DiKsa [7]

Answer:

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let $\mu$ be the random variable that follows a Poisson distribution, then mean $\mu = \dfrac{10}{500}= 0.02$

and the mean that the random selection of 50 pages will contain no error is $\lambda = 50 \times 0.02 =1$

∴

$Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}$

Pr(q =0) = 0.368

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2

$P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]$

$P(X \geq 2) = 1 - [0.3678 +0.3678]$

$P(X \geq 2) = 1 -0.7356$

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0

2 years ago