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Ratling [72]
2 years ago
15

∆ABC and ∆PQR are similar. ∆ABC is dilated by a scale factor of 1.25 and rotated 45° counterclockwise about point B to form ∆PQR

. The side lengths of ∆ABC are , 5 units; , 4.2 units; and , 4 units. Match each side of ∆PQR to its length.
Mathematics
1 answer:
Andrej [43]2 years ago
7 0
This is the concept of transformation of figures, given that ΔABC is similar to ΔPQR, the sides of ABC are 5 units, 4.2 units and 4 units. Since the two triangles are similar and PQR is the image of ABC under the dilation 1.25, the sides of PQR will be:
(5*1.25),(4.2*1.25),(4*1.25)
this will give us:
6.25, 5.25, 5
The length of the sides of PQR are 6.25 units, 5.25 units and 5 units
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faltersainse [42]
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3 > x OR x < 3 (3 is greater/bigger than x which also means x is smaller/lesser than 3)

They are both incorrect.
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2 years ago
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The Big River Casino is advertising a new digital lottery-style game called Instant Lotto. The player can win the following mone
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Answer:

(a) The expected value of the prize for one play of Instant Lotto is $3.50.

(b) The probability that the visitor wins some prize at least twice in the 20 free plays is 0.2641.

(c) The probability that a randomly selected day has at least 1000 people play Instant Lotto is 0.2579.

Step-by-step explanation:

(a)

The probability distribution of the monetary prizes that can be won at the game called Instant Lotto is:

<em>X</em>         P (<em>X</em> = <em>x</em>)

$10        0.05

$15        0.04

$30       0.03

$50       0.01

$1000   0.001

$0         0.869

___________

Total =   1.000

Compute the expected value of the prize for one play of Instant Lotto as follows:

E(X)=\sum x\cdot P (X=x)

         =(10\times 0.05)+(15\times 0.04)+(30\times 0.03) \\+ (50\times 0.01)+(1000\times 0.001)+(0\times 0.869)\\=0.5+0.6+0.9+0.5+1+0\\=3.5          

Thus, the expected value of the prize for one play of Instant Lotto is $3.50.

(b)

Let <em>X</em> = number of times a visitor wins some prize.

A visitor to the casino is given <em>n</em> = 20 free plays of Instant Lotto.

The probability that a visitor wins at any of the 20 free plays is, <em>p</em> = 1/20 = 0.05.

The event of a visitor winning at a random free play is independent of the others.

The random variable <em>X</em> follows Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.05.

Compute the probability that the visitor wins some prize at least twice in the 20 free plays as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-[{20\choose 0}0.05^{0}(1-0.05)^{20-0}]-[{20\choose 1}0.05^{1}(1-0.05)^{20-1}]\\=1-0.3585-0.3774\\=0.2641

Thus, the probability that the visitor wins some prize at least twice in the 20 free plays is 0.2641.

(c)

Let <em>X</em> = number of people who play Instant Lotto each day.

The random variable <em>X</em> is normally distributed with a mean, <em>μ</em> = 800 people and a standard deviation, <em>μ</em> = 310 people.

Compute the probability that a randomly selected day has at least 1000 people play Instant Lotto as follows:

Apply continuity correction:

P (X ≥ 1000) = P (X > 1000 + 0.50)

                    = P (X > 1000.50)

                    =P(\frac{X-\mu}{\sigma}>\frac{1000.50-800}{310})

                    =P(Z>0.65)\\=1-P(Z

Thus, the probability that a randomly selected day has at least 1000 people play Instant Lotto is 0.2579.

5 0
2 years ago
-12.48 -(-2.99)-5.62
KATRIN_1 [288]

Answer:

-15.11

Step-by-step explanation:

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7 0
2 years ago
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Average acceleration: ( v - v o ) / Δ t
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Sphinxa [80]

Answer:

Step-by-step explanation:

erasers=e  

pencils=p

3e+5p=7.55   ...(1)

6e+12p=17.40

divide by 2

3e+6p=8.70  ...(2)

(2)-(1) gives

p=8.70-7.55=1.15

from (1)

3e+5(1.15)=7.55

3e+5.75=7.55

3e=7.55-5.75

3e=1.80

e=1.80/3=0.60

cost of 1 eraser=$0.60

cost of 1 pencil =$1.15

7 0
2 years ago
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