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suter [353]
2 years ago
11

Liliana has a bag of marbles. the bag contains 18 black, 15 red, 11 blue, and 8 white marbles. liliana randomly takes a red marb

le from the bag and leaves the marble on a table. what is the probability that she will next take a red or a white marble from the bag?
Mathematics
1 answer:
likoan [24]2 years ago
4 0
Since you took a red marble from the bag and didn't put it back, you now only have 14 red marbles to pick out of, and the total number of marbles i in your bag is only 51. Probability of choosing red or white is:
(14/51)  + (8/51) = 22/51
You might be interested in
if 5000000 invested at 4% interest compounded continuously how much will the investment be worth in 30 years
umka21 [38]
For this you use A=Pe^(rt)
A=furutre amount
P=present amount
e=natural base
r=rate in decimal
t=times in years

A=?
P=5000000
r=0.04
t=30

A=5,000,000e^(0.04*30)
A=5,000,000e^(1.2)
A=16600584.613683
8 0
2 years ago
Read 2 more answers
Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o
aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)±t_{n_1+n_2-2} * Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }

t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71

[(33.99-26.56) ± 1.654 *(3.71*\sqrt{\frac{1}{135} +\frac{1}{42} })]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485

Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06

[(475.12-321.34) ± 2.485 *(33.06*\sqrt{\frac{1}{12} +\frac{1}{15} })]

[121.96; 185.60]

I hope this helps!

3 0
2 years ago
Smith High School offers a baseball camp that is $75 for 4 days of camp and a basketball camp that is $100 for 5 days of camp. W
castortr0y [4]
A) baseball camp by $1.25 a day

5 0
2 years ago
Read 2 more answers
Mike and Krista rent a jet ski while on vacation. The rental cost is represented by the function c(h)=50+20h, where the number o
Step2247 [10]

Answer:

130

Step-by-step explanation:

Given the equation of the relation as c(h) =50 +20 h where c(h) is the total cost for h hours and h is the number of hours of use, then to find the cost of jet ski if 4 hours were used will be;

c(h)=50 +20 h

c(4)=50 +20*4

c(4)=50 +80

=130

5 0
2 years ago
$abcd$ is a square. how many squares have two or more vertices in the set $\{a, b, c, d\}$?
marshall27 [118]
There are 4 squares having a side corresponding to a side of square abcd.

There are 4 squares having a side corresponding to the diagonals of square abcd.

And then the original square

Therefore, there are 4 + 4 + 1 = 9 squares <span>having two or more vertices in the set {a, b, c, d}.</span>
7 0
2 years ago
Read 2 more answers
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