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VMariaS [17]
2 years ago
9

you roll a number cube twice. find p(even, then not 2). Write the probability as a fraction in simplest form.

Mathematics
2 answers:
ella [17]2 years ago
6 0

Answer:

For the first roll, you expect that you would get an even number. Since there are six sides of a die, then there are 3 ways to get an even number which are numbers 2, 4 and 6. So the probability of an even number is 3/6 or 1/2.

Next for the second roll, you expect that you should not get a number 2. There are 5 ways occurring which are 1, 3, 4, 5, 6. So the probability for this is 5/6.

Multiply the two probabilities because both probabilities will occur for this event.

P(even, then not 2) = (1/2)(5/6) = 5/12

HOPE THIS HELPS !!!

:)

Step-by-step explanation:

aksik [14]2 years ago
4 0
For the first roll, you expect that you would get an even number. Since there are six sides of a die, then there are 3 ways to get an even number which are numbers 2, 4 and 6. So the probability of an even number is 3/6 or 1/2.
Next for the second roll, you expect that you should not get a number 2. There are 5 ways occurring which are 1, 3, 4, 5, 6. So the probability for this is 5/6.
Multiply the two probabilities because both probabilities will occur for this event.
P(even, then not 2) = (1/2)(5/6) = 5/12
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maxonik [38]

Given that:

Total number of fish = 140

Fish are green swordtails female = 44

Fish are green swordtails male = 36

Fish are orange swordtails female = 36

Fish are orange swordtails male = 24

Solution:

A. We have to find the probability that the selected fish is a green swordtail.

\text{P(green swordtail)}=\dfrac{\text{Total green swordtail fish}}{\text{Total fish}}

\text{P(green swordtail)}=\dfrac{80}{140}

\text{P(green swordtail)}=\dfrac{4}{7}

Therefore, the probability that the selected fish is a green swordtail is \dfrac{4}{7}.

B.  We have to find the probability that the selected fish is male.

\text{P(Male fish)}=\dfrac{\text{Total male fish}}{\text{Total fish}}

\text{P(Male fish)}=\dfrac{36+24}{140}

\text{P(Male fish)}=\dfrac{60}{140}

\text{P(Male fish)}=\dfrac{3}{7}

Therefore, the probability that the selected fish is a male, is \dfrac{3}{7}.

C. We have to find the probability that the selected fish is a male green swordtail.

\text{P(Male green swordtail)}=\dfrac{\text{Total male green swordtail fish}}{\text{Total fish}}

\text{P(Male green swordtail)}=\dfrac{36}{140}

\text{P(Male green swordtail)}=\dfrac{9}{35}

Therefore, probability that the selected fish is a male green swordtail is \dfrac{9}{35}.

D.

We have to find the probability that the selected fish is either a male or a green swordtail.

\text{P(Male or green swordtail)}=\dfrac{\text{Total male or green swordtail fish}}{\text{Total fish}}

\text{P(Male or green swordtail)}=\dfrac{44+36+24}{140}

\text{P(Male or green swordtail)}=\dfrac{96}{140}

\text{P(Male or green swordtail)}=\dfrac{24}{35}

Therefore, the probability the selected fish is either a male or a green swordtail is \dfrac{24}{35}.

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James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28.
lara31 [8.8K]
Let's use J for James's age and A for Austin's age. The equations are:

J = A - 4
3J + A² = 28

Just plug (A - 4) in the place of J in the second equation. This gives you:

3(A - 4) + A² = 28
-->
A² + 3A - 12 = 28
--> 
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-->
A = 5 or -8

-8 is nonsense, so Austin is 5 years old. Therefore, James is 1 year old.
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Answer:

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Step-by-step explanation:

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