To evaluate 17 int (sin^2 (x) cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x)
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]

7 0

1 year ago

Which of the following data could be graphed using a dot plot ?

kotegsom [21]

Answer:

number of cards in a house hold and number of siblings

Step-by-step explanation:

6 0

1 year ago

A shipping company charges a $5 flat fee for a package, plus a fee based on the weight of the package. The company charges $1.50

kherson [118]

I believe the maximum number of pounds would be 11.

8 0

1 year ago

Read 2 more answers

Henry constructed circle A with a radius of 4 units. He then created a sector as shown in the figure below. Which of the followi

puteri [66]

The picture in the attached figure

we know that
area of a sector=(∅*pi/360°)*r²--------> when ∅ is in degree

in this problem
∅=120°
r=4 units
so
area of a sector=(120°*pi/360°)*4²-------> (120°/360°)*(16*pi) units²

The <span>expressions to find the area of the shaded sector is
</span>(120°/360°)*(16*pi) units²

(1/3)*(16*pi)----> (16/3)*pi units²

the area of the shaded sector is (16/3)*pi units²

8 0

1 year ago