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ad-work [718]
1 year ago
13

dave is helping his grandmother make trail mix his grandmother asks him to add 1/5 cup of fruit for every 1/3 cup of nuts. To sa

tisfy his grandmother's request, drave must mix ___ cups of fruit for a single cup of nuts
Mathematics
2 answers:
agasfer [191]1 year ago
4 0
Dave needs 3/5 cups of nuts
mr Goodwill [35]1 year ago
4 0
<h2>Answer:</h2>

To satisfy his grandmother's request, drave must mix 3/5 cups of fruit for a single cup of nuts

<h2>Step-by-step explanation:</h2>

It is given that:

1/5 cup of fruit is required for every 1/3 cup of nuts while making a trail mix.

Hence,

1/3 cup of nuts= 1/5 cup of fruit

This means that:

1/3 ×3 cup of nuts=1/5×3 cup of fruit

i.e.  1 cup of nuts=3/5 cup of fruit

                   Hence, the answer is:

     3/5 cups of fruit is required for single cup of nuts.

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2. ½ of a group of chickens tried to cross the road. Only ¾ of those chickens made it to the other side. What fraction of the or
ArbitrLikvidat [17]
Let me help you visualize this one.

Let's say we have 12 chickens.

OOOOOOOOOOOO

We divide this group in half (1/2 who tried to cross the road.)

OOOOOO

And here, we need to get 3/4 of the 6 left.

3/4 can be represented as 0.75 of 1.

6 times 0.75 equals to 4.5.

OOOOC (Woah, that chicken is split in half!)

What fraction is 4.5 of the original amount?

Well, that's for you to find out! Good luck in solving this question.
3 0
1 year ago
Read 2 more answers
How are the two functions f(x) = 0.7(6)x and g(x) = 0.7(6)–x related to each other?
Harlamova29_29 [7]
The answer
f(x) = 0.7(6)x = <span>f(x) = 0.7(6)^x, and  </span><span>g(x) = 0.7(6)–x= </span>g(x) = 0.7(6)^-x=1/<span>0.7(6)^x
so </span>
g(x) =1/<span>0.7(6)^x=1 /</span><span><span>f(x)

</span> the relationship between f and g are </span>g(x) =1 /<span>f(x) or </span><span>g(x) . <span>f(x) = 1</span> </span>






7 0
2 years ago
Read 2 more answers
Use technology or a z-distribution table to find the indicated area.
katrin [286]
Approximately 70% of the visitors to the theme park are older than about 12.3.

A z-score of about -0.53 is position on the normal distribution for finding the amount above 30% (70%).

Therefore, we can write and solve the following equation:

(x - 15) / 5.2 = -0.53
x - 15 = -2.756
x = 12.244

The closest amount is 12.3.
8 0
1 year ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random sample of
nikitadnepr [17]

Answer:

a) Reject H₀

b) [0.31; 3.35]

Step-by-step explanation:

Hello!

a) The objective of this example is to compare if the population means of the production rate of the assembly lines A, B and C. To do so the data of the production of each line were recorded and an ANOVA was run using it.

The study variable is:

Y: Production rate of an assembly line.

Assuming that the study variable has a normal distribution for each population, the observations are independent and the population variances are equal, you can apply a parametric ANOVA with the hypothesis:

H₀ μ₁= μ₂= μ₃

H₁: At least one of the population means is different from the others

Where:

Population 1: line A

Population 2: line B

Population 3: line C

α: 0.01

This test is always one-tailed to the right. The statistic is the Snedecor's F, constructed as the MSTr divided by the MSEr if the value of the statistic is big, this means that there is a greater variance due to the treatments than to the error, this means that the population means are different. If the value of F is small, it means that the differences between populations are not significant ( may differ due to error and not treatment).

The critical region is:

F_{k-1;n-k; 1-\alpha } = F_{2;15; 0.99} = 6.36

If F ≥ 3.36, the decision is to reject the null hypothesis.

Looking at the given data:

F= \frac{MSTr}{MSEr}= 11.32653

With this value the decision is to reject the null hypothesis.

Using the p-value method:

p-value: 0.001005

α: 0.01

The p-value is less than the significance level, the decision is to reject the null hypothesis.

At a level of 5%, there is significant evidence to say that at least one of the population means of the production ratio of the assembly lines A, B and C is different than the others.

b) In this item, you have to stop paying attention to the production ratio of the assembly line A to compare the population means of the production ratio of lines B and C.

(I'll use the same subscripts to be congruent with part a.)

The parameter to estimate is μ₂ - μ₃

The populations are the same as before, so you can still assume that the study variables have a normal distribution and their population variances are unknown but equal. The statistic to use under these conditions, since the sample sizes are 6 for both assembly lines, is a pooled-t for two independent variables with unknown but equal population variances.

t=  (X[bar]₂ - X[bar]₃) - ( μ₂ - μ₃) ~t_{n_2+n_3-2}

Sa√(1/n₂+1/n₃)

The formula for the interval is:

(X[bar]₂ - X[bar]₃) ± t_{n_2+n_3-2; 1 - \alpha /2}* Sa\sqrt{*\frac{1}{n_2} + \frac{1}{n_3} }

Sa^{2} = \frac{(n_2-1)*S_2^2+ (n_3-1)*S_3^2}{n_2+n_3-2}

Sa^{2} = \frac{(5*0.67)+ (5*0.7)}{6+6-2}

Sa^{2} = 0.685

Sa= 0.827 ≅ 0.83

t_{n_2+n_3-2;1-\alpha /2}= t_{10;0.995} = 3.169

X[bar]₂ = 43.33

X[bar]₃ = 41.5

(43.33-41.5) ± 3.169 * *0.83\sqrt{*\frac{1}{6} + \frac{1}{6} }

1.83 ± 3.169 * 0.479

[0.31; 3.35]

With a confidence level of 99% you'd expect that the difference of the population means of the production rate of the assemly lines B and C.

I hope it helps!

8 0
1 year ago
While remodeling her kitchen Angela is repainting. She estimates that she paints 55 square feet every half-hour. How many square
madreJ [45]
110 square feet. 55x2=100
5 0
1 year ago
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