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2 years ago

What is the best approximation of the solution to the system to the nearest integer values?

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

7 0

The best approximation of this system would be around (3.2,5.2)

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11. In a certain town the ratio of the number of cars to that of taxis is 15:4. If

Bess [88]

Answer: 645 cars

Step-by-step explanation:

Divide 172 by 4 to find the multiple which is 43 so if 4 was multiplied by 43 to get 172 taxis you must multiply 15 by 43 which gives 645

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2 years ago

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BRAINLY ANYONE?

Oduvanchick [21]

Answer:

58, 37, 9

Step-by-step explanation:

Given:

First term a₁ = 65 and common difference d = - 7

This sequence is arithmetic series and formula for calculating n-th term is:

aₙ = a₁ + (n-1) d

Accordingly

The second term is:

a₂ = 65 + (2-1) (-7) = 65 - 7 = 58

a₂ = 58

The fifth term is:

a₅ = 65 + (5 - 1) (-7) = 65 + 4 · (-7) = 65 - 28 = 37

a₅ = 37

The ninth term is:

a₉ = 65 + (9 - 1) (-7) = 65 + 8 · (-7) = 65 - 56 = 9

a₉ = 9

God with you!!!

4 0

2 years ago

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In triangle LTM, segment XY is the perpendicular bisector of side TM.

CaHeK987 [17]

The answer is c 100% i know this one lol

5 0

2 years ago

Jeanne makes hair bows to sell at the craft fair. Each bow requires 1.5 yards of ribbon. If Jeanne wants to make 84 bows, how ma

mina [271]

Answer:

Jeanne must buy <u>378 feet</u> of ribbons to make 84 bows.

Step-by-step explanation:

Given:

Each bow required = 1.5 yards of ribbon

Number of bow to make = 84

We need to find the length of ribbon in feet to make 84 bows.

Solution:

First we will find length of ribbons in yards required to make 84 bows .

Now we know that;

1 bow =1.5 yards of ribbons

84 bows = length of ribbons in yards

By using Unitary method we get;

length of ribbons in yards = $1.5\times 84 = 126\ yards$

Now we know that;

1 yard = 3 feet

126 yard = length of ribbons in feet

Again by using Unitary method we get;

length of ribbons in feet to make 84 bows = $126 \times 3 = 378\ ft$

Hence, Jeanne must buy <u>378 feet</u> of ribbons to make 84 bows.

7 0

2 years ago

The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds after being dropped. The b

mel-nik [20]

Answer:

Third option: 5.48

Step-by-step explanation:

Given the quadratic model that represents the approximate height in meters of the ball $f(x)=-5x^2 +200$ . the time in seconds x, when the ball is 50 meters from the ground can be calculated by substituting $f(x)=50$ and solving for x.

Then:

$50=-5x^2 +200$

Subtract 200 from both sides:

$-200+50=-5x^2 +200-200\\-150=-5x^2$

Divide both sides by -5:

$\frac{-150}{-5}=\frac{-5x^2}{-5}\\30=x^2$

Apply square root to both sides:

$\sqrt{30}=\sqrt{x^2}\\\sqrt{30}=x\\5.48=x$

The ball is 50 meters from the ground after about 5.48 seconds.

3 0

2 years ago