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2 years ago

Which is the correct mole ratio for aluminum chloride to chlorine in the chemical reaction AlCl3 + Br2 ® AlBr3 + Cl2?

1 answer:

7 0

Reation goes in the opposite direction: aluminium bromide and chlorine react, aluminium chloride and bromine are formed.

2AlBr₃ + 3Cl₂ = 2AlCl₃ + 3Br₂

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Are all the molecules in the picture the same?

Dvinal [7]

Answer:

There is no picture.

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2 years ago

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g A 0.25 mol sample of HBr is added to a 1.00 L buffer solution consisting of 0.68 M HCN and 0.35 M NaCN. Identify all species t

salantis [7]

Answer:

See explaination for details and diagram

Explanation:

We can say that Chemical reaction is a process in which one or more substances, the reactants, are converted to one or more different substances, the products. Substances are either chemical elements or compounds.

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products.

See attachment for the buffer of the chemical reaction.

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2 years ago

A student runs an experiment in the lab and then uses the data to prepare an Arrhenius plot of the natural log of the rate const

Thepotemich [5.8K]

Answer:

21.86582KJ

Explanation:

The graphical form of the Arrhenius equation is shown on the image attached. Remember that in the Arrhenius equation, we plot the rate constant against the inverse of temperature. The slope of this graph is the activation energy and its y intercept is the frequency factor.

Applying the equation if a straight line, y=mx +c, and comparing the given equation with the graphical form of the Arrhenius equation shown in the image attached, we obtain the activation energy of the reaction as shown.

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2 years ago

The table lists the chemical formulas or symbols of a few common substances. Which two substances are compounds? A) aluminum and

katrin [286]

D is the correct answer

every other option contains an element

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2 years ago

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g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole

Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0

2 years ago