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Olin [163]
2 years ago
12

Which equilibrium expression represents the ionization of water?

Chemistry
2 answers:
Tems11 [23]2 years ago
8 0
Keq = [H3O+][OH-] .............................
pav-90 [236]2 years ago
5 0
H₂O + H₂O ⇄ H₃O⁺ + OH⁻
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A 0.1064 g sample of a pesticide was decomposed by the action of sodium biphenyl. The liberated Cl- was extracted with water and
Ilya [14]

Answer:

Percentage of an aldrin in the sample is 44.41%.

Explanation:

Cl^-+AgNO_3\rightarrow AgCl+NO_{3}^-

Molarity of the silver nitrate solution = 0.03337 M

Volume of the silver nitrate = 23.28 mL = 0.02328 L

Moles of silver nitrate = n

0.03337 M=\frac{n}{0.02328 L}

n = 0.03337 M\times 0.02328 L=0.0007768 mol

According to reaction 1 mole of silver nitrate recats with 1 moles of chloride ions.

Then 0.0007768 moles of silver nitrate will react with:

\frac{1}{1}\times 0.0007768 mol=0.0007768 mol chloride ions.

In one mole of aldrin there are 6  moles of chloride ions.

Then moles of aldrin containing 0.0007768 moles chloride ions are:

\frac{0.0007768 mol}{6}=0.0001295 mol

Moles of aldrin present in the sample = 0.0001295 mol

Mass of 0.0001295 moles of aldrin present in the sample :

0.0001295 mol × 364.92 g/mol =0.04726 g

Percentage of an aldrin in the sample:

\frac{0.04726 g}{0.1064 g}\times 100=44.41\%

8 0
2 years ago
The reading on a speedometer represents the average velocity of the car. True False
Sedbober [7]
Answer: False. Hope this helps!!
7 0
2 years ago
list three sources of error that could account for the differences between your values for the enthalpy of fusion of water and t
NARA [144]

<span>Three sources of error that might account for the differences in the enthalpy of fusion include the room temperature how much’ long you stirred and another thing that might make it have different results is how long the ice was out for   </span>


3 0
2 years ago
A LIQUID HAS THE FOLLOWING PROPERTIES: ONE PHASE, COLORLESS, BOILING POINT 95 TO 97 oC. WHICH OF THE FOLLOWING BEST DESCRIBES A
ololo11 [35]
I think it is D. coarse mixture
hope this helps:)
8 0
2 years ago
3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.
kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

Percent by mass=\frac{mass of solute}{mass of solution} *100

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

  • mass of solute: 3.55 g
  • mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

Percentbymass=\frac{3.55}{91.55}*100

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0
2 years ago
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