Explain how the complement can be used to find the probability of getting at least one item of a particular type
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Answer:
Keith must remove 90-75 = 15 bags in order to meet the weight requirements
Step-by-step explanation:
This problem can be solved by consecutive rules of three problem.
Rule of three problem:
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.
In this problem, the measures are:
- The number of bags
- The total weight
As the number of bags increases, so do the total weight. So, the relationship between the measures is direct.
To know how many bags does Keith need to remove in order to meet the weight requirements, we first need to know how many bags are in the truck currently.
The problem states that each bag weighs 40 pounds and the weight of the truck is 3600 pounds, so:
1 bag - 40 pounds
x bags - 3600 pounds
40x = 3600
x = 90.
Keith currently has 90 bags in the truck.
Now, we have to know how much bags he can have in the truck, that is, 3000 pounds worth of bags. So:
1 bag - 40 pounds
x bags - 3000 pounds
40x = 3000
x = 75.
The truck's capacity is at most 75 bags.
So, Keith must remove 90-75 = 15 bags in order to meet the weight requirements
Answer:
Step-by-step explanation:
The following formula is used to compute the Proportion of error-free units given the sigma level in Excel.
<em> The proportion of error-free units = NORMSDIST(Sigma Level - 1.5) </em>
Suppose that a process is currently operating at a 3.5-sigma quality level.
The proportion of error-free units for this process is
NORMSDIST(3.5 - 1.5) = 0.977250
Therefore, the rejection rate is equal to
or 22750 PPM.
Now, consider a 6-sigma level process.
The proportion of error-free units equals
NORMSDIST(6.0 - 1.5) = 0.9999966
and the rejection rate is
Hence, reduction is PPM required per year , that is
reduction per year