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2 years ago

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At intermission, Xavier sold refreshments. Of the items he had, 1/5 were granola bars and 1/2 the remaining items were container

s of popcorn. The rest were divided equally among apples, rice cakes, and containers of yogurt. Xavier sold the 8 apples he had. How many items did he originally have?

2 answers:

Murrr4er [49]2 years ago

4 0

The answer to this word problem is 60 items, if you want to see how I solved it, just let me know.

Anastaziya [24]2 years ago

4 0

Answer: There are 80 items he originally have.

Step-by-step explanation:

Since we have given that

Part of refreshments were granola = $\dfrac{1}{5}$

Part of refreshments were popcorns = $\dfrac{1}{2}$

Remaining part would be

$1-(\dfrac{1}{5}+\dfrac{1}{2})\\\\=1-\dfrac{7}{10}\\\\=\dfrac{10-7}{10}\\\\=\dfrac{3}{10}$

Since rest were divided equally among apples, rice cakes, and yogurt.

Number of apples sold = 8

Let the total number of items be 'x'.

According to question, it becomes,

$\dfrac{3}{10}\times \dfrac{1}{3}x=8\\\\\dfrac{x}{10}=8\\\\x=80$

Hence, there are 80 items he originally have.

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Step-by-step explanation:

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For the indians,

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x = 130

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To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.95 = 0.05

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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

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b

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c

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Step-by-step explanation:

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The correct answer is

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