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Goshia [24]
2 years ago
14

If a=6 and b=5 what is the value of (A2-b2)2

Mathematics
2 answers:
Elena-2011 [213]2 years ago
4 0
(a^2-b^2)^2

(36-25)^2

11^2

121
attashe74 [19]2 years ago
4 0
(a²-b²)²
a=6 and b=5
(6²-5²)²

pemdas, so simplify inside first
(36-25)²
(11)²
121
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Two fish are put in a man-made lake with no other fish in it. Each month, the fish population triples. Which model and equation
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Answer:

Step-by-step explanation:

The basic model for this growth is the exponential function:  y = a(b)^c, where a is the initial value, b is the growth rate and c is the time.

Here we have P = fish population = (2 fish)(3)^t

8 0
2 years ago
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0
2 years ago
which of the following best describes the memorization technique known as mnemonics? A. using flash cards to practice math equat
svet-max [94.6K]

Answer:

Option B is the answer.

Step-by-step explanation:

Which of the following best describes the memorization technique known as mnemonics?  

B. linking information, such as a new vocabulary word, to a mental image that illustrates it in some fashion.

Memorization of the name allows for memorization of the associated idea. Like to remember rainbow colors, you can memorize Roy G. Biv to  remember the colors of the rainbow.

7 0
2 years ago
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A glass bead has the shape of a rectangular prism with a smaller rectangular prism removed. What is the volume of the glass that
olganol [36]

The volume of the removed portion is 35 cm³.

Step-by-step explanation:

Given,

The length× width× height (L×B×H) of the outer part = 3 cm×3 cm×7 cm

The length× width× height (l×b×h) of the inner part = 2 cm×2 cm×7 cm

To find the volume of the removed portion.

Formula

The volume of the removed portion = volume of outer part - volume of inner part

Volume of rectangular prism = l×b×h

Now,

Volume of outer part = 3×3×7 cm³ = 63 cm³

Volume of inner part = 2×2×7 cm³ = 28 cm³

Hence,

The volume of the removed portion = 63-28 cm³ = 35 cm³

4 0
2 years ago
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Suppose a research paper states that the distribution of the daily sea-ice advance/retreat from each sensor is similar and is ap
Luda [366]

Answer:

The value of the parameter is λ is 0.03553357

Step-by-step explanation:

Consider the provided function.

f(x) = 0.5\lambda e^{-\lambda |x|} for −∞ < x < ∞.

It is given that standard deviation is given as 39.8 km.

Now we need to calculate the value of parameter λ.

The general formula for the probability density function of the double exponential distribution is: f(x)=\frac{e^{-|\frac{x-\mu}{\beta}|}}{2\beta}

Where μ is the location parameter and β is the scale parameter.

Compare the provided equation with the above formula we get.

\lambda=\frac{1}{\beta} and μ = 0.

Standard deviation = √2β

S.D=\sqrt{2} \beta\\\beta=\frac{39.8}{\sqrt{2}}\\\beta=28.1424

Now substitute the value of β in \lambda=\frac{1}{\beta}.

\lambda=\frac{1}{28.1424}=0.03553357

Hence, the value of the parameter is λ is 0.03553357

3 0
2 years ago
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