Answer:
7.5kilometer
Step-by-step explanation:
for 30mins semin runs 5kilometer
then for 1min: (1min×5kilometer)÷30mins,
therefore, for 45mins: (45mins×5kilometer)÷30mins=7.5kilometer
I would go with the second statement is true because if all of the other ones mentioned in the problem had something that would not work either the one before or after would make the statement false excepted for statement two
Answer:
z= 0.278
Step-by-step explanation:
Given data
n1= 60 ; n2 = 100
mean 1= x1`= 10.4; mean 2= x2`= 9.7
standard deviation 1= s1= 2.7 pounds ; standard deviation 2= s2 = 1.9 lb
We formulate our null and alternate hypothesis as
H0 = x`1- x`2 = 0 and H1 = x`1- x`2 ≠ 0 ( two sided)
We set level of significance α= 0.05
the test statistic to be used under H0 is
z = x1`- x2`/ √ s₁²/n₁ + s₂²/n₂
the critical region is z > ± 1.96
Computations
z= 10.4- 9.7/ √(2.7)²/60+( 1.9)²/ 100
z= 10.4- 9.7/ √ 7.29/60 + 3.61/100
z= 0.7/√ 0.1215+ 0.0361
z=0.7 /√0.1576
z= 0.7 (0.396988)
z= 0.2778= 0.278
Since the calculated value of z does not fall in the critical region so we accept the null hypothesis H0 = x`1- x`2 = 0 at 5 % significance level. In other words we conclude that the difference between mean scores is insignificant or merely due to chance.
Answer: it is a right tailed probability
Step-by-step explanation:
Population proportion = 26.9/100 = 0.269
We are dealing with the fact that the probability that the mean bond percent for the sample will be at least 28. This means that the sample proportion is 0.28 or above. This means that it is greater than the population proportion of 0.269
The hypothesis would be
For null hypothesis
p = 0.269
For alternative hypothesis,
p > 0.269
The inequality sign means that it is right tailed.
Answer:

Step-by-step explanation:
we have

we know that
The formula to solve a quadratic equation of the form
is equal to
in this problem we have
so
substitute in the formula

therefore
StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction comma StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction