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babunello [35]
2 years ago
3

What would be the formula of the precipitate that forms when pb(no3)2 (aq) and k2so4 (aq) are mixed? pbk2 pbso4 h2o none of the

above k(no3)2?
Chemistry
1 answer:
Ivahew [28]2 years ago
5 0
The formula of the precipitate that will be formed is PbSO4.
When lead ll nitrate react with potassium sulphate, one of the product formed is lead sulphate. The reaction is a double decomposition precipitation reaction; PbSO4 is the precipitate formed. 
You might be interested in
A cylinder contains 4.0 g of nitrogen gas. A piston compresses the gas to half its initial volume. Afterward, by what factor has
notka56 [123]

Answer:

The mass density will be doubled

Explanation:

  • Density is given by dividing the mass of a substance by its volume.
  • An increase in mass causes an increase in density and vice versa, while a  decrease in volume causes an increase in density and volume.
  • Therefore, when the volume is halved, then the density will be doubled if the mass is kept constant.
  • This has no effect on the number of moles as the mass is constant.
8 0
2 years ago
What is the mass of 3.35 mol Hg(IO3)2? 1,700 g 1,840 g 1,960 g 2,110 g
Tema [17]

Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of Hg(IO_3)_2 and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of Hg(IO_3)_2 = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

= 200.59+253.80+96.00

= 550.39 gram per mol

Let's multiply the given moles by the molar mass:

3.35mol(\frac{550.39g}{1mol})

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.

8 0
2 years ago
A poisoned pill contains 0.00048 moles of KCN. How many molecules are in this sample?
mario62 [17]

Answer:

2.89 \times  {10}^{20}  \:  \: molecules

Explanation:

The number of molecules of KCN can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.00048 × 6.02 × 10²³

We have the final answer as

2.89 \times  {10}^{20}  \:  \:  \: molecules

Hope this helps you

7 0
1 year ago
A 0.8838-g sample of an ionic compound containing bromide ions and an unknown metal cation is dissolved in water and treated wit
Alex17521 [72]
Wow this is really hard dude
4 0
2 years ago
Read 2 more answers
The percent composition by mass of a compound is 76.0% c, 12.8% h, and 11.2% o. the molar mass of this compound is 284.5 g/mol.
Leokris [45]
You have a few steps to solve this one. First, we'll find the molar mass by percentage of each element in the molecule. Then, we'll divide each of those relative masses by the atomic mass of each element. The number of times the mass divides into the relative mass is the number of atoms of that element in the molecule:

C: 284.5 x .76 = 216.22
H: 284.5 x .128= 36.416
O: 284.5 x .112 = 31.864.

Now we divide out each element's atomic mass (from the periodic table). it's okay if they're approximated from the decimal answer.
C: 216.22 ÷ 12.011 ≈ 18
H: 36.416 ÷ 1.008 ≈36
O: 31.864 ÷ 15.999 ≈ 2

Therefore, the molecular formula is C18H36O2. 

The empirical formula would be found by dividing out all factors of those subscript numbers. In our case, all of them can be divided by 2. The empirical formula would be C9H18O




7 0
2 years ago
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