2 years ago

PLEASE HELP

Mathematics

1 answer:

Lesechka [4]2 years ago

7 0

1,800= 45x ( x is the amount of weeks)

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1 decimeter on the map represents 100 meters on the ground. The scale ratio is 1 to ___.

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The monthly profit for a small company that makes long-sleeve T-shirts depends on the price per shirt. If the price is too high,

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Answer:

A. $18

B. $200

C. $p\in (16,20)$

Step-by-step explanation:

Function:

$f(p) = -50p^2 + 1,800p - 16,000$

Parts A and B:

The price that generates the maximum profit is ate vertex of parabola. Find the coordinates of the vertex:

$p_v=\dfrac{-b}{2a}=\dfrac{-1,800}{2\cdot (-50)}=\dfrac{1,800}{100}=18\\ \\f(p_v)=-50\cdot 18^2+1,800\cdot 18-16,000=200$

The price that generates the maximum profit is $18

The maximum profit is $200

Part C:

The company breaks even when the profit is positive. From the graph of the function you can see that the graph of the function is over p-axis for all $p\in (16,20)$ , so the positive profit is for $p\in (16,20)$

In p=16 and p=20, the profit is 0 and when p<16 and p>20, there will be a loss.

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2 years ago

Solve for x in the equation x squared + 14 x + 17 = negative 96. x = negative 7 plus-or-minus 4 StartRoot 6 EndRoot i x = –7 ± 8

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Answer:

$x=-7\pm8i$

Step-by-step explanation:

we have

$x^{2} +14x+17=-96$

Equate to zero

$x^{2} +14x+17+96=0$

$x^{2} +14x+113=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +14x+113=0$

$a=1\\b=14\\c=113$

substitute in the formula

$x=\frac{-14\pm\sqrt{14^{2}-4(1)(113)}} {2(1)}$

$x=\frac{-14\pm\sqrt{-256}} {2}$

Remember that

$i=\sqrt{-1}$

$x=\frac{-14\pm16i} {2}$

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