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SIZIF [17.4K]
2 years ago
8

An exponential function with a base of 1/2 has been vertically compressed by a factor of 3/4 and reflected in the x-axis. It's a

symptote is the line y= -4. What is the equation of the function?
Mathematics
1 answer:
joja [24]2 years ago
7 0
We are asked in this problem to determine the expression of an exponential function given the data above. The standard form of an exponential function is expressed as y = a^x + b was a is the base constant and b is another constant. In this case, a is given to be equal to 1/2. since the graph is said to be shrunk down to 3/4 then the initial expression would have to be y = 3/4*(1/2)^x + b. b is determined through the given asymptote in the problem. An asymptote is an axis or the line in which the graph approaches but never touches. b is equal to -4. In this case, the overall expression is y = 3/4 *(1/2)^x - 4.
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Triangles ABC, EDC, and EFG are similar triangles. The measures of the three interior angles of triangle EFG are °, °, and °.
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Because of the vertical angles theorem, BAC becomes 50°. And angle B is 180-(50+30)=100.

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A collection of 77 quarters and dimes is worth $12.50. How many quarters and dimes are there? Set it up plz
mihalych1998 [28]
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The graph of which function passes through (0,3) and has an amplitude of 3? f (x) = sine (x) + 3 f (x) = cosine (x) + 3 f (x) =
Cloud [144]

Answer:

f(x)=3*cosine(x)

Step-by-step explanation:

We are looking for a trigonometric function which contains the point (0, 3), and has an amplitude of 3.

We know that for a sine function f(x)=sin(x), f(0)= 0; therefore the function we a looking for cannot be a sine function because it is zero at x=0.

However, the cosine function f(x)=cos(x) gives non-zero value at x=0:

f(0)=cos(0)=1

therefore, a cosine function can be our function.

Now, cosine function with amplitude a has the form

f(x)=a*cos(x)

this is because the cosine function is maximum at x= 0 and therefore, has the property that

f(0)=a*cos(0)= a

in other words it contains the point (0, a).

The function we are looking for contains the point (0, 3); therefore, its amplitude must be 3, or

f(x)=3cos(x)

we see that this function satisfies our conditions: f(x) has amplitude of 3, and it passes through the point (0, 3) because f(0)=3

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