I have a past due balance of $87.50 and my new charges are $75.00. I was also charged a late fee of 15% of my past due balance.
2 answers:
Answer:
$175.625
Step-by-step explanation:
Let us figure out late fees on the given past due by finding 15% of 87.50.
Our new total will be the sum of past due balance, late fee and new charges .
Let us substitute our given values in above equation to find our new balance.
Therefore, the new balance will be $175.625.
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Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
Question:
The square of a number decreased by 3 times the number is 28 find all possible values for the number
Answer:
The possible values of number are 7 and -4
Solution:
Given that the square of a number decreased by 3 times the number is 28
To find: all possible values of number
Let "a" be the unknown number
From given information,
square of a number decreased by 3 times the number = 28
Let us solve the above quadratic equation
Using the above formula,
Thus the possible values of number are 7 and -4
Answer:
f(x) = Three-halves (three-halves) Superscript x
f(x) = Two-thirds (three-halves) Superscript x
Step-by-step explanation:
Since, a function in the form of
Where, a and b are any constant,
is called exponential function,
There are two types of exponential function,
- Growth function : If b > 1,
- Decay function : if 0 < b < 1,
Since, In
Thus, it is a decay function.
in
Thus, it is a decay function.
in
Thus, it is a growth function.
in
Thus, it is a growth function.