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abruzzese [7]
2 years ago
14

timothy went to a baseball game. after the game, he wanted to ride the bus home. the red line and the blue line buses both both

stop at the stadium :a red line and the blue line left the stadium at 4:00PM :red line buses were scheduled to leave the stadium every 6 minutes :blue line buses were scheduled to leave the stadium every 8 minutes. If the buses run on schedule when is the next time a red line and a blue line bus will leave together?
Mathematics
2 answers:
Jobisdone [24]2 years ago
4 0
This is a least common multiple question.

6: 6, 12, 18, 24, 30, 36
8: 8, 16, 24, 32, 40, 48

The least common multiple is 24. Therefore, the next time that both lines leave the station will be 4:24 PM.
postnew [5]2 years ago
4 0
We have to calculate the least common multiple of 6 and 8.
6=2.3
8=2³

Least common multiple fo 6 and 8=2³ * 3=8*3=24.

Each 24 minutes the red line and blue line leave together the stadium, therefore the next time will be at 4:24 Pm

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Kirsty counts the number of peas in a sample of pea pods
RoseWind [281]
Mode is most occurring

There is no mode for the peas as there is no score occurring more than once


Median is middle number

So cross of 4 and 5, and 7 and 8

Median is 6


Mean is average


4+5+6+7+8 divided by five


Mean is 6


5 0
2 years ago
Read 2 more answers
a game consists of randomly choosing a bag labelled 1 2 or 3 out of a choice of 100 and then again randomly picking a ball(red o
s344n2d4d5 [400]

Answer:

.44

Step-by-step explanation:

Follow the path for each red

Add the  probabilities for each one

Bag 1 = .35*.6

Bag 2 = .45*.2

Bag 3 = .2*.7

P(red) = .35*.6 + .45* .2 + .2 *.7

          = .44

7 0
2 years ago
Read 2 more answers
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Alona [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

4 0
2 years ago
If the expression (2ya)4 is equivalent to 16y8 , what is the value of A.
Alex Ar [27]
If you meant:

(2ya)^4=16y^8  raise the left side to the power of four

16y^4*a^4=16y^8  divide both sides by 16y^4

a^4=y^4  take the quartic root of both sides

a=±y  
7 0
2 years ago
Colleen plans to start a small business by making and selling skirts. A sewing machine costs $250, and she estimates that she wi
Dmitrij [34]
Let C(x) be the function which calculates the total cost of making x skirts.

There is going to be a fixed constant, 250, to which we will add 15$ per x skirts.


So C(x)=250+15x

Answer: 250+15x
7 0
2 years ago
Read 2 more answers
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