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abruzzese [7]
2 years ago
14

timothy went to a baseball game. after the game, he wanted to ride the bus home. the red line and the blue line buses both both

stop at the stadium :a red line and the blue line left the stadium at 4:00PM :red line buses were scheduled to leave the stadium every 6 minutes :blue line buses were scheduled to leave the stadium every 8 minutes. If the buses run on schedule when is the next time a red line and a blue line bus will leave together?
Mathematics
2 answers:
Jobisdone [24]2 years ago
4 0
This is a least common multiple question.

6: 6, 12, 18, 24, 30, 36
8: 8, 16, 24, 32, 40, 48

The least common multiple is 24. Therefore, the next time that both lines leave the station will be 4:24 PM.
postnew [5]2 years ago
4 0
We have to calculate the least common multiple of 6 and 8.
6=2.3
8=2³

Least common multiple fo 6 and 8=2³ * 3=8*3=24.

Each 24 minutes the red line and blue line leave together the stadium, therefore the next time will be at 4:24 Pm

You might be interested in
A triangle has interior angles measuring 36° and 112°. Which triangles are similar to this triangle? Select True or False for ea
morpeh [17]
Hi there!

Since the interior measures of triangles added up always equals 180 degrees, the other interior angle of the triangle must be 32 degrees. 

180 - 112 - 36 = 32

So, any triangle with interior measures that measure any angles of 36, 112, and 32 degrees are similar.

<span>triangle with interior angles measuring 36° and 32° - true
triangle with interior angles measuring 36° and 148° - false
triangle with interior angles measuring 32° and 112° - true
triangle with interior angles measuring 112° and 148 - </span>false

Hope this helps!
3 0
2 years ago
Read 2 more answers
We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
2 years ago
A 0.2-kilogram red ball is thrown horizontally at a speed of 4 meters per second from a height of 3 meters. A 0.4-kilogram green
Stolb23 [73]

Answer:

option (C) the same

Step-by-step explanation:

In the given question , it is mentioned that the ball of mass 0.2 kilograms is thrown with the velocity of 4 m/s in the horizontal direction

and, the 0.4 kilogram green ball is thrown in the horizontal direction with the velocity of 8 m/s

Here in both the cases no component of velocity in the vertical direction is provided.

Hence, it will be a case of free fall in the vertical direction.

Now,

from Newton's equation of motion, we have

s=ut+\frac{1}{2}at^2

here,  

s is the distance

a is the acceleration

t is the time

in the above equation, mass has no role and the value of acceleration i.e acceleration due to gravity and distance of fall in the vertical direction is same.

Hence, the time taken for both the balls will be same.

Hence,

The correct answer is option (C) the same

7 0
2 years ago
N(17+x)=34x−r<br> I need to solve for x
Paraphin [41]

Answer:

The value of x is, x= \frac{17N+r}{34-N}

Explanation:

Given: N(17+x)=34x-r

Distributive Property states that when a number is multiplied by the sum of two numbers, the first number can be distributed to both of those numbers and multiplied by each of them separately.

If a\cdot(b+c) =a\cdot b + a\cdot c

Now, using distributive property on left hand side of the given expression as:

N\cdot 17+N\cdot x = 34x-r or 17N+Nx = 34x-r

Addition Property of equality state that we add the same number from both sides of an equation.

Add r to both sides of an equation:

17N+Nx+r=34x-r+r

Simplify:

17N+Nx+r=34x

Subtraction Property of equality state that we subtract the same number from both sides of an equation.

Subtract Nx from both sides of an equation;

17N+Nx+r-Nx=34x-Nx

Simplify:

17N+r=34x-Nx

or

17N+r=x(34-N)

Division Property of equality states that we divide the same number from both sides of an equation.

Divide by (34-N) to both sides of an equation;

\frac{17N+r}{34-N}= \frac{x(34-N)}{34-N}

On Simplify:

x= \frac{17N+r}{34-N}





4 0
2 years ago
Read 2 more answers
Sabrina is making an open box
Ad libitum [116K]

Answer:

yay! sabrina is making an open box

4 0
2 years ago
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