Complete this sentence. If volume remains the same while the mass of a substance ________, the density of the substance will____
2 answers:
Explanation:
Density is defined as the mass present in per unit volume.
Mathematically, Density =
Since, density is directly proportional to mass. So, when mass increase then there will be increase in density. And when there is decrease in mass then there will be decrease in density.
Therefore, we can conclude that if volume remains the same while the mass of a substance increases, the density of the substance will also increase.
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Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq= =14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5=
14.5 x (0.15 M) x = (CH₃OH)
0.2818 M = (CH₃OH)
In this kind of exercises, you should use the "ideal gas" rules: PV = nRT
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
= constant
= 
==> P1 * V1 = P2 * V2
V2 =
= 
V2 = 0.00581 m3 = 5.81 L
P should be in Pascal:
445mmHg = 59328Pa
1225mmHg = 163319Pa
V should be in cubic meter:
16L = 0.016 m3
R =
==> P1 * V1 = P2 * V2
V2 =
V2 = 0.00581 m3 = 5.81 L
Answer:
The enthlapy of solution is -55.23 kJ/mol.
Explanation:
Mass of water = m
Density of water = 1 g/mL
Volume of water = 50.0 mL
m = Density of water × Volume of water = 1 g/mL × 50.0 mL=50.0 g
Change in temperature of the water ,ΔT= 27.0°C - 22.3°C = 4.7°C
Heat capacity of water,c =4.186 J/g°C
Heat gained by the water when an unknown compound is dissolved be Q
Q= mcΔT
heat released when 0.9775 grams of an unknown compound is dissolved in water will be same as that heat gained by water.
Q'=-Q
Q'= -983.71 J =-0.98371 kJ
Moles of unknown compound =
The enthlapy of solution :
The enthlapy of solution is -55.23 kJ/mol.