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luda_lava [24]
2 years ago
6

Juanita is making necklaces to give as presents. She plans to put 15 beads on each necklace. Beadsare sold in packages of 20. Wh

at is the least number of packages she can tp make necklaces and have no beads left over?
Mathematics
2 answers:
PtichkaEL [24]2 years ago
4 0
3 packages because you'll have 15 beads left over. which would complete the use of the packages
Alex Ar [27]2 years ago
3 0
3 packages is the anwer hopefully this helped
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Step-by-step explanation:

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7 0
2 years ago
A lake is 200 ft wide.Two boats start to move towards one another from opposite shores.In one minute the first boat goes 40 ft a
ddd [48]

Answer:

After one second, 130 ft

After two second , 60 ft

Step-by-step explanation:

Both boats are moving towards each other,

Speed of first boat = 40 ft/min.

Speed of second boat = 30 ft/min.

So, In one Second they must have covered a total distance of 40 + 30 ft

                                                                                                        = 70 ft.

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So, Distance remained between them after one second = 200 - 70 = 130 ft.

After two seconds , First boat will move my 80 ft and second one will move by 60 ft

So, distance between them will decrease by 140 ft.

Distance between the boats after two seconds = 60 ft.

7 0
2 years ago
Kyle is practicing for a 3-mile race. His normal time is 23 minutes 25 seconds. Yesterday it took him only 21 minutes 38 seconds
diamong [38]

Answer:2:24

Step-by-step explanation:

7 0
2 years ago
Report Error Suppose $P(x)$ is a polynomial of smallest possible degree such that: $\bullet$ $P(x)$ has rational coefficients $\
motikmotik

Answer:

We want a polynomial of smallest degree with rational coefficients with zeros in \sqrt{7}, 1 - \sqrt{6} and -3. The last root gives us the factor (x+3). Hence, our polynomial is

P(x) =(x+3)q(x)

where q is a polynomial with rational coefficients and roots \sqrt{7} and 1 - \sqrt{6}. The root \sqrt{7} gives us a factor x-\sqrt{7}, but in order to obtain rational coefficients we must consider the factor x^2-7.

An analogue idea works with 1 - \sqrt{6}. For convenience write  x - 1 + \sqrt{6} = ( x - 1) + \sqrt{6}. This gives the factor (x-1)^2-6. Hence,

P(x) = (x+3)(x^2-7)((x-1)^2-6)=x^5+x^4-18x^3-22x^2+77x+105

Notice that P(-1)=24. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

P(x) =(1/3)x^5+(1/3)x^4-6x^3-(22/3)x^2+(77/3)x+35

Step-by-step explanation:

We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type x-\sqrt7 will introduce in the expression, we need to multiply by its conjugate x+\sqrt7. Hence, we will obtain x^2-7 that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.

4 0
2 years ago
Write the standard form of the line that contains a slope of and y-intercept of 3. Include your work in your final answer. Type
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Y=mx + b
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7 0
2 years ago
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