Answer: 0.813
Step-by-step explanation:
Let A be the event describes the number of residents believed that the amount of violent television programming had increased over the past 10 years.
& B be the event describes the number of residents believed that the amount of violent television programming had decreased over the past 10 years.
Given : n(A)=721 ; n(B)=454 ; n(A∩B)=362
We know that ,

i.e. 
Also, the total number of U.S. residents surveyed n(S)= 1,000
Then, the proportion of the 1,000 U.S. residents believed that either the amount of violent programming had increased or the overall quality of programming had decreased over the past 10 years will be :-

Hence, the required answer = 0.813
Answer:
mean = 78.4
median = 77.5
mode = 75
This is Right - skewed (positive skewness) distribution
Step-by-step explanation:
<u>Mean:-</u>
The mean (average) is found by adding all of the numbers together and dividing by the number of items and it is denoted by x⁻
mean = 
mean (x⁻ ) = 78.4
The mean of the given data = 78.4
<u>Median:</u>
The median is found by ordering the set from lowest to highest and finding the exact middle.
64 ,75, 80, 98
The middle term of the given data set = 
<u>Mode :</u>
The mode is the most common repeated number in a data set.
64 ,75, 75, 80, 98
in data the most common number = 75
<u>Conclusion</u>:-
mean = 78.4
median = 77.5
mode = 75
This is Right - skewed (positive skewness) distribution
the expected value for the 3 point shot = (3 * 0.30) + (0 * 0.70) = 0.90
the expected value for the 2 point shot = (2 * 0.48) + (0 * 0.52) = 0.96
the expected value for the 2 point shot is higher than the 3 point shot so he should pass the ball
A because if he started at negative ten you would add the 10 he increased. When you add those two together you get 0.
-10+10=0