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zaharov [31]
2 years ago
8

Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The

probability of Ahmed winning the checkers game is 0.360.360, point, 36. Which of these events is more likely? Choose 1 answer: Choose 1 answer: (Choice A) A Ahmed wins the chess game. (Choice B) B Ahmed wins the checkers game. (Choice C) C Neither. Both events are equally likely.
Mathematics
1 answer:
Brilliant_brown [7]2 years ago
7 0

Answer: A - Ahmed wins the chess game

Step-by-step explanation:

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a university theater sold 556 tickets for a play, tickets cost $22 per adult tickets and $ 12 for senior citizen ticket, if the
Deffense [45]
Let no. of adult tickets be x and senior citizen tickets be y. x + y = 556 22x + 12y = 8492 Solving by simultanous equations, x = 182 adult tickets y = 374 senior citizen tickets
7 0
2 years ago
Metro buses are scheduled to arrive at each stop every 30 minutes. If the time a person waits at a bus stop is uniformly distrib
Nutka1998 [239]

Answer:

The probability is P(X > 25 )  =  1.667

Step-by-step explanation:

From the question we are told that

    The  maximum wait is  b  = 30 \ minutes

      The  minimum wait would be  a =  0\  minutes

Generally the probability that you will wait more than 25 minutes for a bus is mathematically represented as

   P(X > 25 )

Now given that the time a person waits is uniformly distributed and that the maximum is  30 then we can evaluate the above probability as

    P(X > 25 ) =  P(25 <  X  <  30 ) =  \frac{30 - 25}{30 -  0}

     P(X > 25 )  =  1.667

4 0
1 year ago
Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56
kogti [31]

Answer:

24.2(to the nearest tenth)

Step-by-step explanation:

The question is ungrouped data type

standard deviation =√ [∑ (x-μ)² / n]

mean (μ)=∑x/n

           = \frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}

          =33.3

x-μ   for data 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84 will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

(x-μ)² will be 800.89, 800.89,745.29,453.69,53.29,13.69,246.49,313.29,515.29,515.29,2570.49

∑ (x-μ)² will be = 7028.59

standard deviation = √(7028.59 / 12)

                      =24.2

     

6 0
2 years ago
Round 4.265 to the nearest hundredth
jekas [21]
4.265 rounded to the nearest hundredth is 4.27
3 0
2 years ago
Crop researchers plant 15 plots with a new variety of corn. The yields in bushels per acre are: 138.0 139.1 113.0 132.5 140.7 10
son4ous [18]
There is a relationship between confidence interval and standard deviation:
\theta=\overline{x} \pm \frac{z\sigma}{\sqrt{n}}
Where \overline{x} is the mean, \sigma is standard deviation, and n is number of data points.
Every confidence interval has associated z value. This can be found online.
We need to find the standard deviation first: 
\sigma=\sqrt{\frac{\sum(x-\overline{x})^2}{n}
When we do all the calculations we find that:
\overline{x}=123.8\\ \sigma=11.84
Now we can find confidence intervals:
($90\%,z=1.645): \theta=123.8 \pm \frac{1.645\cdot 11.84}{\sqrt{15}}=123.8 \pm5.0\\($95\%,z=1.960): \theta=123.8 \pm \frac{1.960\cdot 11.84}{\sqrt{15}}=123.8 \pm 5.99\\ ($99\%,z=2.576): \theta=123.8 \pm \frac{2.576\cdot 11.84}{\sqrt{15}}=123.8 \pm 7.87\\
We can see that as confidence interval increases so does the error margin. Z values accociated with each confidence intreval also get bigger as confidence interval increases.
Here is the link to the spreadsheet with standard deviation calculation:
https://docs.google.com/spreadsheets/d/1pnsJIrM_lmQKAGRJvduiHzjg9mYvLgpsCqCoGYvR5Us/edit?usp=sharing
6 0
2 years ago
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