Answer:
The coefficient of O2 is 11
Explanation:
Step 1:
The equation for the reaction:
FeS2 + O2 → SO2 + Fe2O3
Step 2:
Balancing the equation. The equation can be balance as follow:
FeS2 + O2 → SO2 + Fe2O3
There are 2 atoms of Fe on the right side and 1 atom on the left. It can be balance by putting 2 in front of FeS2 as shown below:
2FeS2 + O2 → SO2 + Fe2O3
There are 4 atoms of S on the left side and 1 atom on the right side. It can be balance by putting 4 in front of SO2 as shown below:
2FeS2 + O2 → 4SO2 + Fe2O3
Now, there are a total of 11 atoms of O on the right side and 2 atoms on the left side. It can be balance by putting 11/2 in front of O2 as shown below:
2FeS2 + 11/2O2 → 4SO2 + Fe2O3
Multiply through by 2 to clear the fraction as shown below:
4FeS2 + 11O2 → 8SO2 + 2Fe2O3
Now the equation is balanced.
The coefficient of O2 is 11
The students with ionic bonds have a better understanding of what the model needs to illustrate.
Explanation:
- When ionic compounds dissolve in water, they break apart into the ions that make them up through a process called dissociation.
- When placed in water, the ions are attracted to the water molecules, each of which carries a polar charge.
- If the force between the ions and the water molecules is strong enough to break the bonds between the ions, the compound dissolves.
- The ions dissociate and disperse in solution, each ringed by water molecules to prevent reattachment.
- The ionic solution turns into an electrolyte, meaning it can conduct electricity.
- While covalent compounds dissolve in water they break apart into molecules, but not individual atoms.
- Water is a polar solvent, but covalent compounds are usually nonpolar.
- This means covalent compounds typically don't dissolve in water, instead making a separate layer on the water's surface.
Answer:
Passivation of Oxide layers of the metals.
Explanation:
Passivation is a non-electrolytic finishing process that makes most metals rust-resistant. The prosses removes free iron from the surface by using either nitric or citric acid. When this happens, it results to an inert, protective oxide layer that is very slow or less likely to chemically react with air and cause corrosion.
Passivity caused many of the metals several minutes to begin to react. Once the finishing process that makes metals less likely to react was eroded, reaction was initiated vigorously.
1500 cm^3 ; 1 mL equals 1 cm^3
