It took many of the metals several minutes to begin to react. Once the reaction was initiated, several of these metals continued
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A.) The conversion factor is 1 amu = 
To know how many amu in
grams of neutrons:
=1.00811 amu
b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.
= 
c.) How many amu in 6.492x10^-23g potassium?
= 39.0957 amu
To know how many amu in
=1.00811 amu
b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.
c.) How many amu in 6.492x10^-23g potassium?
Answer:
Net ionic equation for the reaction between MgCl₂ and NaOH in water:
.
Net ionic equation for the reaction between MgSO₄ and BaCl₂ in water:
.
Explanation:
Start by finding the chemical equations for each reaction:
MgCl₂ reacts with NaOH to form Mg(OH)₂ and NaCl. This reaction is a double decomposition reaction (a.k.a. double replacement reaction, salt metathesis reaction.) This reaction is feasible because one of the products, Mg(OH)₂, is weakly soluble in water and exists as a solid precipitate.
.
MgSO₄ reacts with BaCl₂ in a double decomposition reaction to produce BaSO₄ and MgCl₂. Similarly, the solid product BaSO₄ makes this reaction is feasible.
.
How to rewrite a chemical equation to produce a net ionic equation?
- Rewrite all reactants and products that ionizes completely in the solution as ions.
- Eliminate ions that exist on both sides of the equation to produce a net ionic equation.
Typical classes of chemicals that ionize completely in water:
- Soluble salts,
- Strong acids, and
- Strong bases.
Keep the formula of salts that are not soluble in water, weak acids, weak bases, and water unchanged.
Take the first reaction as an example, note the coefficients:
- MgCl₂ is a salt and is soluble in water. Each unit of MgCl₂ can be written as
and
.
- NaOH is a strong base. Each unit of NaOH can be written as
and
.
- Mg(OH)₂ is a weak base and should not be written.
- NaCl is a salt and is soluble in water. Each unit of NaCl can be written as
.
.
Ions on both sides of the equation:
.
Add the state symbols:
.
For the second reaction:
.
.
.