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nikdorinn [45]
2 years ago
3

Which of the following spreadsheets shows the financial plan with the greatest net cash flow?

Mathematics
2 answers:
-Dominant- [34]2 years ago
7 0
Net cash flow is given  by gross cash flow minus the expenses

Spreadsheet 1:
Gross cash flow (cash inflow) = $2350
Cash outflow (expenses) = 2335
Net cash flow = 2350 - 2335 = $15

Spreadsheet 2:
Gross cash flow (cash inflow) = $2270
Cash outflow (expenses) = $2260
Net cash flow = 2270 - 2260 = $10

Spreadsheet 3:
Gross cash flow (cash inflow) = $2380
Cash outflow (expenses) = $2380
Net cash flow = 2380 - 2380 = 0

Spreadsheet 4:
Gross cash flow (cash inflow) = $2150
Cash outflow (expenses) = $2055
Net cash flow = 2150 - 2055 = $100

Answer: Spreadsheet 4
strojnjashka [21]2 years ago
5 0

Answer:

spreadsheet 4 (D)

Step-by-step explanation:

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What kind of salad do snowmen eat? Punchline 73 answer key
motikmotik

Answer:

Coldslaw

Step-by-step explanation:

6 0
2 years ago
A camera manufacturer spends $1,800 each day for overhead expenses plus $9 per camera for labor and materials . The cameras sell
kobusy [5.1K]
A) set x as the number of cameras
18x=9x+1800
9x=1800
x=200

b) i'm assuming it's increasing production from my answer in a, so the profit would be 18(250)-(9*250+1800)=4500-4050=450
4 0
2 years ago
Find the first partial derivative:<br><br> f(x, y) = y^5 -3xy
Romashka-Z-Leto [24]
Partial derivative is derivative over only 1 variable.
here we have 2 variables so it depends on which variable you want to make partial derivative.

case 1. 
df/dx = -3y

case 2
df/dy = 5y^4 - 3x
8 0
2 years ago
Hospital sends an invoice to a patient. The patient schedules a payment plan in which she makes an initial payment of $1,451 the
Korvikt [17]
First month she payed 1451 dollars

Second month she payed 1/3 of that, which is:
1451/3 = 483.66

Third month she payed 1/3 of 483.66 because as text says, every next month she pays 1/3 of previous month payed amount.

483.66/3 = 161.22

Forth month she payed

161.22/3 = 53.74

In total she payed:

$2149.62 - B.

hope this helps :)
3 0
2 years ago
Read 2 more answers
N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle
zmey [24]

<u>Answer-</u>

The standard error of the confidence interval is 0.63%

<u>Solution-</u>

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

M=\frac{x}{n} =\frac{255}{2373} =0.1075

Then the standard error SE will be,

SE=\sqrt{\frac{M\times (1-M)}{n}}

SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%

Therefore, the standard error of the confidence interval is 0.63%




6 0
2 years ago
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