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Kay [80]
2 years ago
4

a cough medicine has 17.5% active ingredient. if the dose is 5 mL, how much of the dose is active ingredient?

Chemistry
2 answers:
Anna007 [38]2 years ago
8 0

Answer: 0.875 mL is present active ingredient in a 5 mL of dose.

Explanation:

Volume of the cough medicine or dose = 5 mL

Percentage of the active ingredient = 17.5 % of the dose

Volume of the active ingredient in 5 mL of dose :

5 mL\times \frac{17.5}{100}=0.875 mL

0.875 mL is present active ingredient in a 5 mL of dose.

Dafna1 [17]2 years ago
8 0
The volume of the dose = 5 mL.
The active ingredient is 17.5% of the dose, therefore it has a volume of
0.175*(5 mL) = 0.875 mL

Answer: 0.875 mL
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Each student in a class placed a 2.00 g sample of a mixture of Cu and Al in a beaker and placed the beaker in a fume hood. The s
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Answer:

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Explanation:

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3 0
2 years ago
Nickel can be plated from aqueous solution according to the following half reaction. How long would it take (in min) to plate 29
andrey2020 [161]

Answer:

It take 3.5 *10² min

Explanation:

Step 1: Data given

Mass of the nickel = 29.6 grams

4.7A

Step 2: The balanced equation

Ni2+ (aq- +2e- → Ni(s)

Step 3: Calculate time

W = (ItA)/(n*F)

  ⇒ W = weight of plated metal in grams = 29.6

 ⇒ I = current in coulombs per second. = 4.7

 ⇒ t = time in seconds.

 ⇒ A = atomic weight of the metal in grams per mole. = 58.69

 ⇒ n = valence of dissolved metal in solution in equivalents per mole.  = 2

 ⇒ F = Faraday's constant in coulombs per equivalent. F = 96,485.309               coulombs/equivalent.

29.6 = (4.7 * t * 58.69)/(2*96485309)

t = 20707 seconds

t =345 minutes = 3.5 * 10² min

It take 3.5 *10² min

7 0
2 years ago
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