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2 years ago

What is the solution set for the quadratic equation x squared - 16 equals 0

2 answers:

8 0

$x^2-16=0 \\\\ (x-4)(x+4)=0 \\\\\\ \#1 \\\\ x+4=0 \\\\ \boxed{x=-4} \\\\ \#2 \\\\ x-4=0 \\\\ \boxed{x=4} \\\\\\ \boxed{\boxed{S=\{ -4;4 \}}}$

LenaWriter [7]2 years ago

3 0

X is either 4 or -4 because it is the square root of 16

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The floor area of a hall is 1044 m2. The length is 36 m. Give a quick estimate of width of the hall. ?

wolverine [178]

36m. Im not sure but thats what i got, hope it helps...

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2 years ago

The growth in the mouse population at a certain county dump can be modeled by the exponential function A(t)= 906e0.012t, where t

tatyana61 [14]

Answer:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 months into the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

Step-by-step explanation:

We know that the population can be represented with this formula:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 monthsinto the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

5 0

2 years ago

Factorise 15x+25<br><br>thank you for any help

scoray [572]

Answer: 5(3x+5)

Step-by-step explanation:

To factor this expression we need to pull out the greatest common factor of the 2 numbers, 15 and 25. This factor is 5.

Now divide both numbers by 5 and put a 5 on the outside of the new expression to look like: $5(3x+5)$ and this is as far as it can be factored.

4 0

2 years ago

Read 2 more answers

Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o

AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

$\frac{1}{8} x +\frac{1}{2} y = 52$

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

$\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52$

$\frac{1}{8} x - 8 + \frac{1}{2} x = 52$

$\frac{1}{8} x + \frac{1}{2} x - 8 = 52$

Take common denominator to combine fractions

$\frac{1}{8} x + \frac{4}{8} x -8 = 52$

$\frac{5}{8} x - 8 = 52$

Add 8 on both sides

$\frac{5}{8} x = 60$

Multiply both sides by $\frac{8}{5}$

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

6 0

2 years ago

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Fran graphs the equations y = 2x2 – 2 and y = –0.5x + 4. Her graph is shown below. mc010-1.jpg Which value is an approximate sol

miv72 [106K]

On the added picture you can see that graphs of functions $y=2x^2-2$ and $y=-0.5x+4$ have two points of intersection. The x-coordinates of these points are the solutions of the equation
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Hence, the approximate solutions are x=-1.9 and x=1.6.

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2 years ago

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