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aliya0001 [1]
2 years ago
3

(EMG) Which sequence contains elements listed from most reactive to least?

Chemistry
1 answer:
Alenkasestr [34]2 years ago
3 0
<span>1. Alkali metals, alkaline earth metals, noble gases In general, the reactivity of an element is related to how full it's outer electron shell is. If it's almost empty and only needs to lose 1 electron, it's highly reactive. If it's almost full and only needs to gain 1 electron, it's also highly reactive. If it's completely full and doesn't need to gain or lose an electron, it's practically inert and non-reactive. As it gets closer to being only half full, it tends to be less reactive. With that in mind, let's look at the choices and see if they make sense. 1. Alkali metals, alkaline earth metals, noble gases Alkali metals - First column of periodic table. Only 1 electron in its valance shell. Very reactive. alkaline earth metals - Second column of periodic table, Only 2 electrons in their valiance shells. Still quite reactive, but not as much as the Alkali metals. noble gases - Last column of the periodic table. Valance shell full. Very non-reactive. Overall, this looks like a very good choice. 2. Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity. Wrong answer. 3. Alkaline earth metals, alkali metals, halogens Alkaline earth metals - 2 valance electrons. Pretty reactive. alkali metals - 1 valance electron, extremely reactive. Bad choice, going from lower reactivity to higher reactivity. Wrong answer. 4. Transition metals, noble gases, halogen Transition metals - Middle of periodic table, average reactivity. noble gases - Full valance shells, non-reactive. halogen - Missing 1 electron from their valance shells. Highly reactive. Bad choice, medium, low, high. Not a consistent trend from reactive to non-reactive. Wrong answer.</span>
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The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of
AlexFokin [52]

Answer: C. 25.6 kPa

Explanation:

The Gauge pressure is defined as the amount of pressure in a fluid that exceeds the amount of pressure in the atmosphere.

As such, the formula will be,

PG = PT – PA

Where,

PG is Gauge Pressure

PT is Absolute Pressure

PA is Atmospheric Pressure

Inputted in the formula,

PG = 125.4 - 99.8

PG = 25.6 kPa

The gauge pressure inside the container is 25.6kPa which is option C.

4 0
2 years ago
What would have happened to your results if during the dehydration some of the copper (ii) sulfate splatter out of the crucible-
lidiya [134]

Answer : The results would show more amount of water in the hydrated sample.

Explanation :

The amount of water of crystallization can be found by taking the masses of hydrated copper sulfate and anhydrous copper sulfate.

The difference in masses indicates the mass of water lost during dehydration process.

If during dehydration process, some of the copper sulfate spatters out of the crucible, then this would give us less mass for anhydrous sample than the actual.

As a result, the difference in masses of hydrated sample and the anhydrous sample would be more.

Therefore the results would show more amount of water in the hydrated sample.

4 0
2 years ago
A metal sample is heated and placed into the water in a calorimeter at room temperature. Which statement best describes how the
andre [41]

Answer:

Energy transfers from the metal to the water and calorimeter until they are all at room temperature.

Explanation:

CHECK THE COMPLETE QUESTION BELOW;

A metal sample is heated and placed into the water in a calorimeter at room temperature. Which statement best describes how the calorimeter can be used to determine the specific heat capacity of the metal sample?

Energy transfers to the metal from the water and calorimeter until they are all at room temperature

. Energy transfers from the metal to the water and calorimeter until they are all at room temperature.

Energy transfers to the metal from the water and calorimeter until they all reach a single temperature.

Energy transfers from the metal to the water and calorimeter until they all reach a single temperature.

EXPLANATION;

Using calorimeter to determine the specific heat capacity of the metal sample can be associated to the theory of conservation of energy because heat which is a form of energy is been transfer of heat between the metal to the water and the calorimeter, this process will proceed till single temperature is attained.

The change in the amount of temperature of the water in the calorimeter is measured in order to get the difference in heat change of the calorimeter water.

CHANGE IN HEAT CAN BE CALCULATED USING THE FORMULA.

Q = cmΔT where Q is the change in heat , c is the specific heat capacity and ΔT is the change in temperature

6 0
2 years ago
If 3.491 grams of the precipitate was formed, how many moles of strontium bromide were reacted
AVprozaik [17]
The balanced chemical equation that represents the reaction is as follows:
 <span>SrBr2(aq) + 2AgNO3(aq) → Sr(NO3)2(aq) + 2AgBr(s) 
</span>
From the periodic table:
mass of silver = 108 grams
mass of bromine = 80 grams

molar mass of silver bromide = 108 + 80 = 188 grams

number of moles = mass / molar mass
number of moles of produced precipitate = 3.491/188 = 0.018 moles

From the balanced equation:
1 mole of  strontium bromide produces 2 moles of silver bromide. Therefore, to calculate the number of moles of <span>strontium bromide that produces 0.018 moles of silver bromide, you will just do a cross multiplication as follows:
amount of </span><span>strontium bromide = (0.018x1) / 2 = 9.28 x 10^-3 moles</span>
4 0
2 years ago
If 36.9 mL of B2H6 reacted with excess oxygen gas, determine the actual yield of B2O3 if the percent yield of B2O3 was 75.7%. (T
zhuklara [117]

Answer: The actual yield of B_2O_3 is 60.0 g

Explanation:-

The balanced chemical reaction :

B_2H_6(l)+3O_2(g)\rightarrow B_2O_3(s)+3H_2O(l)

Mass of B_2H_6 =Density\times Volume=1.131g/ml\times 36.9ml=41.7g

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} B_2H_6=\frac{41.7g}{27.668g/mol}=1.51moles

According to stoichiometry:

1 mole of B_2H_6 gives = 1 mole of B_2O_3

1.51 moles of B_2H_6 gives =\frac{1}{1}\times 1.51=1.51 moles of B_2O_3

Theoretical yield of B_2O_3=moles\times {Molar mass}}=1.14mol\times 69.62g/mol=79.3g

Percent yield of B_2O_3= 75.7\%

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

75.7\%=\frac{\text{Actual yield}}{79.3}\times 100

{\text{Actual yield}}=60.0g

Thus the actual yield of B_2O_3 is 60.0 g

7 0
2 years ago
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