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Citrus2011 [14]
2 years ago
5

Tony misplaced 777 stamps from his collection. He knows that each stamp of his is worth \$0.15$0.15dollar sign, 0, point, 15 and

that the total value of them is now only \$5.55$5.55dollar sign, 5, point, 55.
Mathematics
2 answers:
asambeis [7]2 years ago
7 0
There is no question being asked. If the answer needed is how many stamps does he have left take the total value and divide by the worth of each stamp. 5.55/0.15 = 37
Anettt [7]2 years ago
7 0

Write an equation to represent the value of his stamp collection in terms of the number of stamps, s, that he had originally, and find the value of s.

Tony misplaced 7 stamps

Each stamp worth = $0.15

Total value of stamp now = $5.55

Let the number of stamps be 's'

Number of stamps now = s - 7 (misplaced 7 stamps)

price (number of stamps now ) = 0.55

0.15 (s - 7) = 5.55

Divide by 0.15 on both sides

s - 7 = 37

Add 7 on both sides

s = 44

Total number of stamps originally he had = 44 stamps

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Compute i^1+i^2+i^3....i^99+i^100
fgiga [73]

Good morning ☕️

Answer:

<h3>i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰ = 0</h3>

Step-by-step explanation:

Consider the sum S = i¹ + i² + i³ +. . .+ i⁹⁹ + i¹⁰⁰

S =  i¹ +  i² +  i³ + . . . + i⁹⁹  +  i¹⁰⁰

S = a₁ + a₂ + a₃ +. . . + a₉₉ + a₁₀₀

then, S is the sum of 100 consecutive terms of a geometric sequence (an)

where the first term a1 = i¹ = i  and the common ratio = i

FORMULA:______________________

S=(term1)*\frac{1-(common.ratio)^{number.of.terms}}{1-(common.ratio)}

_______________________________

then

S=i*\frac{1-i^{100} }{1-i}

or i¹⁰⁰ = (i⁴)²⁵ = 1²⁵ = 1  (we know that i⁴ = 1)

Hence

S = 0

7 0
2 years ago
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
2 years ago
Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented
sp2606 [1]

Answer:  The answer is A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


Step-by-step explanation: Given that the area of the whole circle is represented by the expression

A_c=25x^2-12x-9.

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.

Thus, the area of the outer ring is

A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.


5 0
2 years ago
C. Assessment
Crazy boy [7]
1. B
2. A
3. A
All of theses are true
4 0
2 years ago
The density of granite is about 2.75 grams per cubic centimeter. Suppose you have a granite countertop for a kitchen that is 1 m
stellarik [79]

Answer:

330\ kg

Step-by-step explanation:

Remember that

1 kg=1,000 g

1 m= 100 cm

The volume of the granite countertop in cubic centimeters is equal to

V=(100)(300)(4)\ cm^{3}

The density in kg per cubic centimeter is equal to

D=2.75(\frac{1}{1,000}) \frac{kg}{cm^{3}}

Multiply the density by the volume

2.75(\frac{1}{1,000})(100)(300)(4)

2.75(120)=330\ kg

6 0
2 years ago
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