Ask question

Ask question

All categories

2 years ago

13

1. Helene’s credit card has an APR of 16.8%. She never pays her balance in full, so she always pays a finance charge. Her next b

illing cycle starts today. The billing period is 30 days. Today’s balance is $712.04. She is only going to use the credit card this month to make a $5,000 down payment on a new car

1 answer:

antiseptic1488 [7]2 years ago

8 0

Take the 712.04 out of the credit card month number and then multiply by 16.8%

You might be interested in

In the diagram below, circle O is circumscribed about quadrilateral DEFG. What is the value of x?

earnstyle [38]

Answer:

A. $61^{o}$

Step-by-step explanation:

We are told that circle O is circumscribed about quadrilateral DEFG.

Since we know that the opposite angles of quadrilateral inscribed inside a circle are supplementary.

Let us find value of x by equating the measure of x and its opposite angle with 180.

$x+119^{o}=180^{o}$

$x=180^{o}-119^{o}$

$x=61^{o}$

Therefore, the value of x is 61 degrees and option A is the correct choice.

5 0

2 years ago

Read 2 more answers

The mass of a colony of bacteria, in grams, is modeled by the function P given by P(t)=2+5tan^−1.(t/2), where t is measured in d

ira [324]

Answer:

1.21 g/day

Step-by-step explanation:

We are given that

The mass of a colony of bacteria (in (grams) is given by

$P(t)=2+5tan^{-1}(\frac{t}{2})$

Where t=Time(in days)

Differentiate w.r.t t

$P'(t)=5(\frac{1}{1+\frac{t^2}{4}}\times \frac{1}{2})$

By using the formula $\frac{d(tan^{-1}(x)}{dx}=\frac{1}{1+x^2}$

$P'(t)=\frac{5}{2}(\frac{4}{4+t^2})$

$P'(t)=\frac{10}{4+t^2}$

We are given P(t)=6

Substitute the value

$6=2+5tan^{-1}(\frac{t}{2})$

$5tan^{-1}(\frac{t}{2})=6-2=4$

$tan^}{-1}(\frac{t}{2})=\frac{4}{5}$

$\frac{t}{2}=tan(\frac{4}{5})$

$t=2tan(\frac{4}{5})$

Substitute the value of t

$P'(2tan\frac{4}{5})=\frac{10}{4+4tan^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{10}{4}\times \frac{1}{1+tan^2(\frac{4}{5})}$

We know that $1+tan^2\theta=sec^2\theta$

Using the formula

$P'(2tan(\frac{4}{5})=\frac{5}{2}\times \frac{1}{sec^2(\frac{4}{5})}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times cos^2(\frac{4}{5})$

By using $cos^2x=\frac{1}{sec^2x}$

$P'(2tan\frac{4}{5})=\frac{5}{2}\times (0.696)^2=1.21$ g/day

Hence,the instantaneous rate of change of the mass of the colony=1.21g/day

7 0

2 years ago

Read 2 more answers

What is the 8th term of the binomial expansion (x + y)10?

12345 [234]

We can use the Pascal's Triangle to solve this problem. This pascal's triangle is shown in the figure below. To build the triangle, begin with the number 1 at the top, then continue placing numbers below it in a triangular pattern. In this way, each number are the numbers directly above added together. So, the expression:

$(x+y)^{10}$

Can be extended as follows, for n = 10:

$(x+y)^{10}=x^{10}+10x^{9}y+45x^{8}y^2+120x^{7}y^3+210x^{6}y^4+252x^{5}y^5+210x^{4}y^6+120x^{3}y^7+45x^{2}y^8+10xy^9+y^{10}$

So, the 8th term of the binomial expansion is:

$120x^{3}y^7$

4 0

2 years ago

Assume that triangle GHI is congruent to LMN. Which of the following congruence statement are correct? check all that apply

Airida [17]

If two triangles are congruent, then they have equal corresponding angles and also the sides.
Therefore, if GHI is congruent to LMN, then GH =LM, HI=MN and GI=LN, and also angle G=angle L, Angle H=angle M, while angle I = angle N, therefore the correct answers is a) ∠M= ∠H, c) ∠L=∠G. and e)IH=NM.

5 0

2 years ago

Read 2 more answers

Segment YB is x+3 units long and segment BW is 2x-9 units long. The diagonal YW is ___ units long.

Gnom [1K]

Answer:

3x - 6

Step-by-step explanation:

Segment YB = x + 3

Segment BW = 2x - 9

Add the two segments.

x + 3 + 2x - 9

3x - 6

The diagonal YW is 3x - 6 units long.

6 0

2 years ago

Read 2 more answers