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julia-pushkina [17]

2 years ago

5

Rectangle EFGH is translated according to the rule T–5, 9(x, y). If the coordinates of the pre-image of point H are (–2, –3), wh

at are the coordinates of H'?

2 answers:

photoshop1234 [79]2 years ago

7 0

H' = -2 -5, -3 + 9 = (-7, 6)

tatyana61 [14]2 years ago

3 0

Answer:

(-7,6)

Step-by-step explanation:

Just took test on edgen

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Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

3 0

2 years ago

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime

Aleks [24]

Answer:

Its A

Step-by-step explanation:

i just took the quiz and got it right

8 0

2 years ago

Read 2 more answers

Consider the incomplete paragraph proof. Given: Isosceles right triangle XYZ (45°–45°–90° triangle) Prove: In a 45°–45°–90° tria

Norma-Jean [14]

Answer:

(C)Determine the principal square root of both sides of the equation.

Step-by-step explanation:

Given: Isosceles right triangle XYZ (45°–45°–90° triangle)

To Prove: In a 45°–45°–90° triangle, the hypotenuse is $\sqrt{2}$ times the length of each leg.

Proof:

$\angle XYZ$ is 90^\circ$ and the other 2 angles are 45^\circ. \\\overline{XY} = a, \overline{YZ}= a, \overline{XZ}= c.\\$

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, $a^2 + b^2 = c^2$

Since a=b in an isosceles triangle:

$a^2 + a^2 = c^2\\$Combining like terms\\2a^2 = c^2\\$Determine the principal square root of both sides of the equation.\\\sqrt{c^2}=\sqrt{2a^2} \\\\c=a\sqrt{2} \\$

Therefore, the next step is to Determine the principal square root of both sides of the equation.

8 0

2 years ago

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Which description best compares the graphs of the two functions below?

Pavlova-9 [17]

Some of your pic is cut off so it's difficult to give the exact answer. But if you plot the points from the table you get that the equation for that set of data is linear and is y = 1/3x -2. This tells me that the y-intercepts are the same for both equations, so your answer is not the first or the third. Because the slope of the function A is 3 and for B is 1/3, the line for function A is steeper, the second of your choices above.

7 0

2 years ago

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Which ordered pairs in the form (x, y) are solutions to the equation 3x – 4y = 21? Choose all answers that are correct.

bekas [8.4K]

A. (−3, 3)
<span>3x – 4y = 21
</span>3(-3) - 4(3) = 21
-21 = 21 >>>>> not equal

B. (−1, −6)
<span>3(-1) - 4(-6) = 21
</span>21 = 21 >>>>>>>>>>Equal

C. (7, 0)
<span>3(7) - 4(0) = 21
</span>21 = 21>>>>>>>>>>equal

D. (11, 3)
<span>3(11) - 4(3) = 21
</span>21 = 21 >>>>>>>>>equal

5 0

2 years ago

Read 2 more answers