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Alexxx [7]
2 years ago
3

A basket of negligible weight hangs from a vertical spring scale of force constant 1500 n/m . if you suddenly put an adobe brick

of mass 3.00 kg in the basket, find the maximum distance that the spring will stretch.

Physics
2 answers:
pashok25 [27]2 years ago
7 0
Refer to the diagram shown below.

k = 1500 N/m, the spring constant
W = (3 kg)*(9.8 m/s²) = 29.4 N, the weight of the brick

Let d =  the deflection of the spring.
By definition,
W = k*d
d = (29.4 N)/(1500 N/m) = 0.0196 m

Answer: 0.0196 m

kumpel [21]2 years ago
3 0
<span>The maximum distance the spring will stretch is 3.92 cm or 0.0392 m.</span>
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1. 5.0 x 10^2 C

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A 6.0-μF capacitor charged to 50 V and a 4.0-μF capacitor charged to 34 V are connected to each other, with the two positive pla
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Explanation:

Given that :

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A 0.20-kg object attached to the end of a string swings in a vertical circle (radius = 80 cm). at the top of the circle the spee
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Explanation:

Convert the radius of the circle to meters:

r = 80\;\text{cm} = 0.80\;\text{m}.

What's the net force on the object?

The object is in a circular motion. As a result,

\displaystyle \Sigma F = \frac{m\cdot v^{2}}{r},

where

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  • v is the velocity of the object, and
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For this object,

\displaystyle \Sigma F = \frac{0.20\times {4.5}^{2}}{0.80} = 5.0625\;\text{N}.

The output unit of net force should be standard if the unit for mass, velocity, and radius are all standard. The net force shall always point towards the center. In this case the net force points downwards.

What are the forces on this object?

There are two forces on the object at this moment:

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What's the size of the tension force?

Gravity and tension points in the same direction. The size of their resultant force is the sum of the two forces. In other words,

\Sigma F = T + W.

T = \Sigma F - W = 5.0625 - 1.962 = 3.1.

All three values in this question are given with two sig. fig. Round the value of T to the same number of significant figures.

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