Answer:
1) 64.2 mi/h
2) 3.31 seconds
3) 47.5 m
4) 5.26 seconds
Explanation:
t = Time taken = 2.5 s
u = Initial velocity = 0 m/s
v = Final velocity = 21.7 m/s
s = Displacement
a = Acceleration
1) Top speed = 28.7 m/s
1 mile = 1609.344 m

1 hour = 60×60 seconds


Top speed of the cheetah is 64.2 mi/h
Equation of motion

Acceleration of the cheetah is 8.68 m/s²
2)

It takes a cheetah 3.31 seconds to reach its top speed.
3)

It travels 47.5 m in that time
4) When s = 120 m

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds
Answer:
C
Explanation:
From above question we know that
A = 6.2 m
f = 1.6 rad/s
t = 3.5 s
x =?
We know that,
x = Acos(2pie ft)
Putting all values in above eq.
x = 6.2 x cos(2x3.142x1.6x3.5)
x = - 4.8
Displacement can never be negative so ignore - sign.
Answer:Average speed is greater than average velocity.
Explanation :
Given
student walks slowly along a straight line for a while ,then stops to rest a while, and finally runs quickly back to her initial position
Let x be the length of track and the whole process takes t time
For average speed 
Average speed
For average velocity 
Since displacement is zero as she returns to its initial position.
Average velocity=0
Therefore Average speed is greater than average velocity.