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erik [133]
2 years ago
12

Given the polynomial 21x 4 + 3y - 6x 2 + 34

Mathematics
1 answer:
padilas [110]2 years ago
5 0
The given polynomial is 21x⁴ + 3y - 6x² + 34

We want to subtract a polynomial, f(x) so that
21x⁴ + 3y - 6x² + 34 - f(x) = 29x² - 7

Therefore
-f(x) = 29x² - 7 - (21x⁴ + 3y - 6x² + 34)
       = -21x⁴ + 35x² - 3y - 41

Answer: 21x⁴ - 35x² + 3y + 41
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Which facts could be applied to simplify this expression? Check all that apply.
kykrilka [37]

The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.

C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.

D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.

Hope this helps!

3 0
2 years ago
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Devon exercised the same amount of time each day for 5 days last week. e His exercise included walking and swimming. e Each day
prohojiy [21]
I think that Devon swam at least 35 minutes each day for 5 days because if he exercised 225 minutes and each day he walked for 10 minutes then if you divide 225 by 5 you get 45 so every day he exercised 45 minutes and since he walked for 10 minutes you subtract 10 from 45 which gives you 35 so he swam for 35 minutes.
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A machine is made up of 3 components: an upper part, a middle part, and a lower part. the machine is then assembled. 5 percent o
a_sh-v [17]
10 out of 100 are defective
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2 years ago
Best Company sells personalized mugs for $18 each plus a fixed fee of $26 for shipping and handling for the entire order. The Cu
Step2247 [10]

26+18m = 14+22m

26 + 18m-22m=14

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8 0
2 years ago
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If a random variable X is exponentially distributed with parameter λ=2, then P(X≥1) is equal to
Rasek [7]

Answer:

D. 0.1353

B. 0.0473

Step-by-step explanation:

For an exponentially distributed random variable, the cumulative distribution function is:

P(x\leq a) = 1 - e^{-\lambda a}\\P(x\geq a) = e^{-\lambda a}

with parameter λ=2, then P(X≥1) is equal to:

P(x\geq 1) = e^{-2*1}=0.1353

D. 0.1353

with parameter λ=1.5, then P(2≤X≤4) is equal to

P(2\leq x \leq 4) = P(x \leq 4) - P(x\leq 2)\\P(2\leq x \leq 4) =1 - (e^{-1.5*4}) - (1-(e^{-1.5*2}))\\P(2\leq x \leq 4) = 0.0473

B. 0.0473

7 0
2 years ago
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