Answer:
1) Find the probability that a chosen book is nonfiction and hard-covered. P(N ∩ H) = 4/20
2) Find the probability that a chosen book is hard-covered. P(H) = 11/20
3) Calculate the conditional probability. = 4/11
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1.) 4/20
2.) 11/20
3.) 4/11
Given
One month julia collected 8.4 gallons of rainwater.
she used 5.2 gallons of rainwater to water her garden
6.5 gallons of rainwater to water flowers
Find out how much was the supply of rainwater increased or decreased by the end of the month.
To proof
As given in the question
One month julia collected 8.4 gallons of rainwater
she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers
Total water she used in the month = 5.2 gallons + 6.5gallons
= 11.7 gallons
Let the supply of rainwater increased or decreased by the end of the month
be x .
Than the equation become in the form
x + 8.4 = 11.7
x = 3.3 gallons
Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.
Hence proved
Answer:
No. The results of the survey cannot be generalized to the population of all customers of the shopping mall.
Step-by-step explanation:
Survey results are biased, because data is collected from customers who came trough one specific door of the mall.
Some of the customers <em>may be using some other door </em>where satisfaction survey is not given to these people while passing the door.
Therefore survey results does not reflect thoughts of the population of all customers.
Question: The sample data and the scatter plot was not added to your question. See the attached file for the scatter plot.
Answer: Yes
Step-by-step explanation:
From scatter plot, it was discovered that there is a linear relationship between the two variables and both variables are quantitative.
Therefore, it appropriate to use the correlation coefficient to describe the strength of the relationship between "Time" and "Fish Quality"?
We know that sin(a-b) = sina.cosb - cosa.sinb
if a=70 & b=10 the sin(70-10) = sin(60) = √3/2
Sin70cos10-cos70sin10 = sin60 = √3/2